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In-s [12.5K]
3 years ago
15

Write an expression to represent: Six more than the quotient of four and a number ..

Mathematics
1 answer:
Galina-37 [17]3 years ago
6 0

Answer:

4/x+6

Step-by-step explanation:

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32/24

Step-by-step explanation:

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13/26 = x/24 solve for x <br> PLEASE ANSWER
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x= 12

Step-by-step explanation:

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Gemiola [76]

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42cm^2

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Please HELP!!! I'll make you Brainliest!!!!
erica [24]

Answer: 1. d. 7x\geq 350; x\geq 50

2. a. (5, 28)

3. a: C(n) = 0.90 n - 0.40

Step-by-step explanation:

1. Here x represents the saving of one day.

Thus, the total saving for 7 day = 7 x

And, my  goal is to save at least $350.00  ( According to the question)

⇒ 7x\geq 350

⇒  x\geq 50 ( by dividing both sides by 7 )

Therefore, Option d is correct.

2. since, if a point satisfies an equation then we can say that it is the solution of the equation.

(5,28) satisfies y= 5x + 3

Because at x = 5, 5×5 + 3 = 25 + 3 = 28

except this point other points (28, 5), (4, 20) and (3, 19) are not satisfying given equation of line.

Therefore, only (5,28) is the solution of line.

⇒ Option a is correct.

3. Here n represents the number of tunas.

And, according to question the cost of one tuna = $0.90

⇒ Cost of n tunas = $ 0.90n

But again according to the question,

I have a coupon for $0.40 off your total purchase.

Thus, $ 0.40 will be less from my total purchasing cost.

⇒ The cost of n tunas = $ (0.90 n - 0.4)

Option a is correct.



7 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
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