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mojhsa [17]
3 years ago
12

HELPP FASTT WILL GIVE BRAINLIEST ANSWER AND THANKS!!!!!!

Mathematics
1 answer:
qaws [65]3 years ago
3 0
Y>2 is the 1st one. x>-4 is the 3rd one. Write the inequality. 1. 3, 2. 3
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Please help me with this. Just have to write the equation. If you can solve, then you get brainliest guaranteed!
Temka [501]

x = player1

y = player 2

z = player 3

y = 2x  or 1/2 y =x

y = z-10  or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

1/2y + y + y+10 = 70

2.5 y + 10 = 70

subtract 10 from each side

2.5 y = 60

divide by 2.5 on each side

y = 60/2.5

y =24

x = 1/2 y

x = 1/2 *24 = 12

z = y+10 = 24+10 = 34

The three players scored 12, 24, 34


4 0
3 years ago
Read 2 more answers
A square garden has an area of 144ft^2 .<br>What is the length side of the garden?
Vladimir [108]
12, because 144^2/2=12
4 0
3 years ago
g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len
vredina [299]

Answer:

-\frac{10}{3}ft/s

Step-by-step explanation:

We are given that

Height of man=5 foot

\frac{dy}{dt}=-10ft/s

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

\frac{20}{5}=\frac{x+y}{x}

4=\frac{x+y}{x}

4x=x+y

4x-x=y

3x=y

3\frac{dx}{dt}=\frac{dy}{dt}

\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=-\frac{10}{3}ft/s

7 0
3 years ago
Six identically shaped place mats, marked a, b, c, d, e and f, are piled neatly in a stack. how many arrangements are possible i
Sedaia [141]
6
1. A, b, c
2. A, b, d
3. A, b, e
4. C, a, b
5. D, a, b
6. E, a, b

Hope I helped!
5 0
3 years ago
How to find the distance from a velocity-time graph?
Orlov [11]

Answer:

Calculating the distance travelled

Calculate the total distance travelled by the object - its motion is represented by the velocity-time graph below.

Here, the distance travelled can be found by calculating the total area of the shaded sections below the line.

½ × base × height.

½ × 6 × 2 = 12 m 2

(10 – 6) × 2 = 8 m 2

6 0
3 years ago
Read 2 more answers
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