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Semenov [28]
3 years ago
7

What guides a researcher when deciding between using either linear, logistic, or Cox proportional hazards regression as an analy

sis tool

Mathematics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

The outcome variable type (continuous, binary, or time -to- event)

Explanation:

The outcome variable type is the type of variables involved in a research. The researcher would put the type of variable involved in his research into consideration in deciding what regression model to apply in his research. For example, if the type of variable in his research are continuous variables(continuous variables are variables that may be any value within a range and may be infinite), he would use linear regression

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The Potter Valley basketball team did not record how many baskets each player made during the last game. Jenny remembers that sh
lesya692 [45]

Answer:  The approximate values that every player make are,

Tammy = grace = 5.43 baskets

Jenny = 16.30 Baskets

Alex = 11.43 Baskets

Joan = 1.43

Step-by-step explanation:

Let Grace made x baskets.

Then According to the question,

Jenny made baskets = 3x

Alexis made basket = x + 6

Joan made basket = x - 4

Tammy made baskets = x

Since,  Altogether the five players made 40 baskets.

⇒ x+ 3x + x + 6 + x - 4 + x = 40

⇒ 7x + 2 = 40

⇒ 7x = 38

⇒ x = 38 / 7 = 5.42857142857 ≈ 5.43

Thus, Grace made baskets= Tammy made baskets = x = 5.43

Jenny made baskets = 3 × x = 16.2857142857 ≈ 16.30

Alexis made basket = x + 6 = 11.4285714286  ≈ 11.43

Joan made basket = x - 4 = 1.42857142857

≈ 1.43




5 0
3 years ago
COOKING Franklin is cooking a 3-pound turkey breast for 6 people. If the number of pounds of turkey varies directly with the num
Gwar [14]

<u>Answer-</u>

2, 4, and 8 people will need 1, 2, 4 pounds of turkey respectively.

<u>Solution-</u>

Given in the question, number of pounds of turkey varies directly with the number of people, i.e as the number of people increases or decreases, the pound of turkey also increases or decreases.  

Taking,

x = number of people,

y = pounds of turkey.

This condition can be represented as,

\Rightarrow y\ \alpha \ x\\\Rightarrow y=kx

As given in the question, when x = 6 y = 3

\Rightarrow 3=k\times 6

\Rightarrow k=\frac{3}{6}= \frac{1}{2}

Now, putting the values of k in the equation, the equation becomes

\Rightarrow y=\frac{1}{2}x

Now, we can get the values of y or number of pounds of turkey needed by putting the given x or number of people.

All the calculations are shown in the attached table.


5 0
3 years ago
Use distributing property : (-11) x (-15) + (-11) x (-25) plzz answer fast
Semmy [17]
The answer is 440.
What I do is just take the -11 and -15 out of the parentheses so it is -11*-15 and the answer is 165. Then, you take -11 and -25 out of the parentheses and find the answer.
Add them together.
Hope that helped :)
5 0
3 years ago
What is the smallest whole number that is a multiple of 5, 9, and 12?
Marianna [84]

Answer:180

Step-by-step explanation:

you start by finding the prime factorization of the number

5=1*5

9=3*3

12=2*2*3

the shortest way to find the factors is to find is most of them like example, at max, there are 2 two's, 2 three's and 1 five then you multiply them all together

4*9*5=180 and that's the answer

7 0
3 years ago
Read 2 more answers
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
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