<u>Answer:</u> The volume of hydrogen gas that will be collected is 1.85 L
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of aluminium = 1.35 g
Molar mass of aluminium = 27 g/mol
Putting values in above equation, we get:

For the given chemical reaction:

As, hydrochloric acid s present in excess. So, it is considered as an excess reagent.
Thus, aluminium is a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
2 moles of aluminium produces 3 moles of hydrogen gas
So, 0.005 moles of aluminium will produce =
of hydrogen gas
To calculate the mass of helium gas, we use the equation given by ideal gas:
PV = nRT
where,
P = Pressure of hydrogen gas = 743 Torr
V = Volume of the helium gas = ?
n = number of moles of hydrogen gas = 0.075 mol
R = Gas constant = 
T = Temperature of hydrogen gas = ![21^oC=[21+273]K=294K](https://tex.z-dn.net/?f=21%5EoC%3D%5B21%2B273%5DK%3D294K)
Putting values in above equation, we get:

Hence, the volume of hydrogen gas that will be collected is 1.85 L