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Daniel [21]
3 years ago
15

Two shopping carts are pushed with the same force. One cart has a larger mass than the other. How does the mass of the shopping

carts affect their acceleration?
Question 9 options:

The cart with the smaller mass will accelerate faster.


The cart with the larger mass will accelerate faster.


The cart with the smaller mass will not accelerate as fast as that with the larger mass.


Both shopping carts will accelerate at the same rate since they are the same size.
Chemistry
2 answers:
OlgaM077 [116]3 years ago
8 0

Answer: The correct answer is the cart with the smaller mass will accelerate faster.

Explanation: According to Newtons Second Law, the net force is the product of the mass of the object and the acceleration of that object. The acceleration is in the same direction as that of the net force.

Mathematically,

F=ma

where,

F = net force

m = Mass of the object

a = acceleration of the object

In the question,

Force applied on two shopping carts is the same and mass of first cart is more than the mass of the second card.

F_1=F_2\\m_1>m_2

Acceleration is equal to \frac{F}{m}

As, acceleration is inversely proportional to the mass of the object, more the mass of the object less will be its acceleration and the object will move slowly.

Hence, the cart with smaller mass will accelerate faster than the cart having larger mass.

Harman [31]3 years ago
5 0
This would problem will be answered using the concept of momentum. Momentum is the mass times the velocity, where mass is inversely proportional to the velocity. This would mean that an object with greater mass will travel at a much lesser velocity, or vice versa.

Hence, the cart with the smaller mass will accelerate faster.
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CH3 + HCl <=> CH3Cl + H2O
dmitriy555 [2]

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

4 0
3 years ago
you see a coin at the bottom of a fountain of water but when you reach for it it is in another place than it appears to be
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Varvara68 [4.7K]

Answer:

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- Explain how ionic bonds, covalent bonds, and metallic bonds each form and how.
-Dominant- [34]

Answer:  -Ionic bonds form when one atom provides electrons to another atom. Covalent Bonds: Covalent bonds form when two atom shares their valence electrons. Metallic Bonds: Metallic bonds form when a variable number of atoms share a variable number of electrons in a metal lattice.

-Covalent Bonds.

Covalent Compounds. Contain no metals and no ions. Covalent compounds contain nonmetals only.

Example:

Ionic Compounds. A metal with a non-metal. Doesn't use prefixes for naming. Name the metal and change the nonmetal ending to -ide.

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6 0
2 years ago
The nutritional energy content (in Calories) present in 86g of broccoli with 6g of carbohydrates, 2.6g of protein, and 0.3g of f
asambeis [7]

Answer:

37.1 calories.

Approximately, 37.1 = 40 calories.

Explanation:

So, without mincing words let's dive straight into the solution to the question above.

We are given the following parameters which are going to help in solving this particular Question.

The mass of broccoli = 86g of broccoli, mass of carbohydrates present = 6g of carbohydrates, the mass of protein present = 2.6g of protein and the mass of fat present = 0.3g of fat.

Therefore, the nutritional energy content (in Calories) = (6 × 4) + (2.6 × 4) + (0.3 × 9) = 10.4 + 24 + 2.7 = 37.1

Hence, the nutritional energy content (in Calories) = 37.1 calories.

Approximately, 37.1 = 40 calories.

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