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ivann1987 [24]
3 years ago
14

How much mercury and oxygen could be obtained from 21.7g of mercury (II) oxide

Chemistry
1 answer:
Musya8 [376]3 years ago
7 0

20.06 g of Hg  and 1.6 g of O₂

<u>Explanation:</u>

To Find:

Number of Mercury and oxygen that can be obtained from 21.7 g of HgO

First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,

2 HgO (s) → 2Hg(l) + O₂ (g)

21.7 g of HgO  = \frac{21.7 g}{216.59  g / mol}  

                         = 0.1 mol of HgO.

As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .

So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)

                                                 = 20.06 g of Hg

Amount of oxygen produced = 0.05  mol × 32 g/ mol = 1.6 g of O₂

Thus it is clear that 20.06 g of Hg  and 1.6 g of O₂  is obtained from 21.7 g of HgO

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Answer:

\boxed {\boxed {\sf 1.62 \ g \ Pt}}

Explanation:

We are asked to find the mass of a number of platinum (Pt) atoms.

<h3>1. Convert Atoms to Moles </h3>

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<h3>2. Convert Moles to Grams </h3>

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<h3>3. Round</h3>

The original measurement of atoms ( 4.99 ×10²¹ ) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 6 in the thousandth place tells us to round the 1 up to a 2.

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There are approximately <u>1.62 grams of platinum</u> in 4.99 ×10²¹ atoms of platinum.

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