20.06 g of Hg and 1.6 g of O₂
<u>Explanation:</u>
To Find:
Number of Mercury and oxygen that can be obtained from 21.7 g of HgO
First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,
2 HgO (s) → 2Hg(l) + O₂ (g)
21.7 g of HgO =
= 0.1 mol of HgO.
As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .
So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)
= 20.06 g of Hg
Amount of oxygen produced = 0.05 mol × 32 g/ mol = 1.6 g of O₂
Thus it is clear that 20.06 g of Hg and 1.6 g of O₂ is obtained from 21.7 g of HgO
Answer:
The frequencies of the two lines are:
a)
b)
When we heat rubidium compound we will see red color.
Explanation:
c = speed of light
= wavelength of light
a) Frequency of the light when wavelength is equal to
This frequency corresponds to red light
b) Frequency of the light when wavelength is equal to
This frequency corresponds to violet light
When we heat rubidium compound we will see red color.
Answer:
Explanation:
S is in 3d period, so it has 3 levels
1 level has 2 electrons, 2d level 8 electrons, 3d level 6 electrons