Answer:
First option
Explanation:
Students 1 and 2 have precise measures yet is is not accurate since they measure around 5.
Answer:
B) H2SO4 (aq) + Ca(OH)2 (aq) → CaSO4 (aq) + 2 H2O(l)
Explanation:
A is a reaction between a salt FeCl3 and a base KOH
C is a n acid decomposing on it's own to form two products
D is mercury, a metal reacting with oxygen. Two elements reacting. Neither are an acid or a base
E. is an acid reacting with a metal to liberate hydrogen. There is no base
Answer:
S = 21.92 %
F = 78.08 %
Explanation:
To find the percent composition of each element in SF6, we must find the molar mass of SF6 first.
Molar mass of SF6 = 32 + 19(6)
= 32 + 114
= 146g/mol
mass of Sulphur (S) in SF6 = 32g
mass of Fluorine (F) in SF6 = 114g
Percent composition = mass of element/molar mass of compound × 100
- % composition of S = 32/146 × 100 = 21.92%.
- % composition of F = 114/146 × 100 = 78.08%.
I farted it tickled my butt cheeks jingled it was hot it was squishy so I did it again
6.022x10^23 is Avogadro’s number. Use this whenever you work with Stoichiometry involving Atoms, formula units, or molecules. 1 mol of anything is always Avogadro’s number.
Multiply everything on the top= 6.93 x 10^23
Divide by everything on the bottom = 6.93 x 10^23
Answer: 6.93 x 10^23 atoms Cu.