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Molodets [167]
3 years ago
12

Exterior of scalene triangle sides are 25 and 15 and x. solve x.

Mathematics
2 answers:
Lyrx [107]3 years ago
5 0

-- All three sides of a scalene triangle have different lengths.
So 'x' can't be 15 and it can't be 25.

-- 'x' must be 10 or more in order to reach between the ends
of the 25 and the 15.

-- 'x' must be less than 40 in order for the 25 and the 15 to reach
between its ends. 

So the value of 'x' must satisfy these conditions:

<em>0 < x < 15</em>
<em>15 < x < 25</em>
<em>25 < x < 40</em>

Any number that satisfies these conditions is an acceptable value for 'x'.


arlik [135]3 years ago
5 0
Let's say we have a triangle with three side lengths.
This triangle is really flat. So much so that you could put it on a number line.
It literally cannot get any flatter, and the largest side literally cannot get any bigger.
Well, the smaller two sides would <em>add <u />up</em> to equal the third.

From this we have realized something: The largest side of any triangle cannot be larger than the sum of the other two.

Let's think back to our problem.
What are the possibilities for x?

If x was the biggest side, it couldn't be any bigger than 40.

If x was a smaller side, then that would make 25 the bigger side.
15 and x together can't be any bigger than 25, so x has to be less than 10.

Since it's a scalene triangle, x cannot be 15 or 25 either, so add that too.

\{x|10\ \textless \ x\ \textless \ 40,\ x\neq15, x\neq25\}
<em />
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Jamar's car used 1/40 ​ of a gallon to travel 3/8 ​ of a mile. How many miles can the car go on one gallon of gas?
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Answer:

15 miles.

Step-by-step explanation:

3/8 x 40 = 120/8

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A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
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Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

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Answer:

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Step-by-step explanation:

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First step is to put all the same ones together

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(z^2 +z^2) + (zx - zx)

2x^2 + 2y^2 + 2z^2

All the others just cancel themselves out, for example, xy-xy

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