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3 years ago

Are the ratios 2.5:3.5 and 5:7 proportional? explain

Mathematics

1 answer:

yuradex [85]3 years ago

3 0

$\frac{2.5}{3.5}=\frac{2.5 \times 2}{3.5 \times 2}=\frac{5}{7}$

They are the same fraction, so they are proportional.

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A lorry weighs 4.65 tonnes. It carries a load of 748 kg. What is the total weight of the lorry and its load?

evablogger [386]

(4.65 tonnes)+(748 kg) =5.39800 tonnes

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3 years ago

Read 2 more answers

What is the volume of the oblique cylinder rounded to the nearest cm^3?

SVETLANKA909090 [29]

Answer: $32009355.90cm^3$

Step-by-step explanation:

Formula: $V=Bh\\$

Since the base is a circumference, we can replace B for the area of a circumference formula.

$V=\pi r^2h$

What we have here is 12 ft as the diameter of the circumference. A diameter is twice the radius, therefore we can conclude that if we take the diameter and divide it by 2, it will give us the radius.

$12/2=6ft$ this is the radius.

Now plug all this information into your formula.

$V=(3.14)(6ft)^2(10ft)\\V=(3.14)(36ft^2)(10ft)\\V=1130.40ft^3$

Our values are in feet but the question requires cm. Let's convert from $ft^3$ to $cm^3$ .

Normally, our conversion factors are raised to the power of 1, but in this case it's raised to the power of 3. So, first let's see how many cm are 1 ft.

$1ft=30.48cm$

Here is where magic comes. We can raise both to the power of 3, in order to find the cubic ft and cm that we need as our conversion factors.

$(1ft)^3=(30.48cm)^3\\1ft^3=28316.8cm^3$

Now we have our conversion factors.

$1130.40ft^3(\frac{28316.84cm^3}{1ft^3})=32009355.90cm^3$

4 0

3 years ago

Is this answer right

ehidna [41]

Answer: No the real answer is 35.10585

Step-by-step explanation:

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3 years ago

Please Help me, Ive Been Stuck On This Question For Ages. :C (Image in question) (And Questions As Well)

MArishka [77]

The answer is the third one.

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3 years ago

Given: ZDEF is a right angle. Using a paragraph proof, prove 41 is acute.

Slav-nsk [51]

Let G be some point on the diagonal line away from point E.

Angle DEG represents angle 1.

We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.

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Extra side notes:

If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.

If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.

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3 years ago