Answer:
electrons have a negative charge
Explanation:
Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%
A shape is the form of an object or its external boundary, outline, or external surface, as opposed to other properties such as color, texture, or material type.
Volume is the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains. Volume is often quantified numerically using the SI derived unit, the cubic metre.
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Molarity of stock solution (M₁) = 15.7 M
- Volume of diluted solution (V₂) = 12 L
- Molarity of diluted solution (M₂) = 0.156 M
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume of the stock solution needed</h3>
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
The acid dissociation constant(Ka) is 0.0095
The reaction for this dissociation of acid is
HSO4 ⇄H+ + SO4 -2
The dissociation constant can be determined from the following expression
[H+] = 10-PH
= 10-1.35
[H+] = 0.0447
[H+] = 0.0447 mol / L
From equation, [H+] = [SO4-2] = 0.0447 mol / L
[SO4-2] = 0.0447 mol / L
From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,
Ka = 0.0447 * 0.0447 / 0.200
= 0.0019 / 0.200
= 0.0095
Hence the value of the acid dissociation constant (Ka) for the given reaction is 0.0095
Learn more about the acid dissociation constant on
brainly.com/question/10038290
#SPJ1