Find the total mass in kilograms of a ring that contains a 5.0 x 10 -1 carat diamond and 7.00 grams of gold.

Minerals with the silicon-oxygen structure shown in Figure 2-1 are classified into what group?

egoroff_w [7]

B----------- oxide is the correct answer

6 0

2 years ago

How many moles of water are produced if 5.43 mol PbO2 are consumed?<br><br> ANSWER: 10.9

Arada [10]

Answer: 10.9 mol.

Explanation:

To understand how to solve this problem, we must mention the reaction equation where water produced from PbO₂.

Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O

Now, it is a stichiometric oriented problem, that 1 mole of PbO₂ produces 2 moles of H₂O.

Using cross multiplication:

1.0 mole of PbO₂ → 2.0 moles of H₂O

5.43 moles of PbO₂ → ??? moles of water

The moles of water produced = (5.43 x 2.0) = 10.86 moles ≅ 10.9 moles.

4 0

3 years ago

Read 2 more answers

Which statement is an opinion?

Zepler [3.9K]

C. or A. Is your best bet

8 0

2 years ago

Read 2 more answers

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

Artemon [7]

<h3>Answer:</h3>

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

<h3>Explanation:</h3>

Balanced equations are equations that obey the law of conservation of mass.
When an equation is balanced the number of atoms of each element is equal on both side of the equation.

Equations are balanced by putting appropriate coefficients on the reactants and products.
In our case, we are going to put coefficients 2, 1 and 1.

Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.

8 0

2 years ago

The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is

WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

$sp^{3}$ , four electron domains, as in ethane $\text{C}_2\text{H}_6$
$sp^{2}$ , three electron domains, as in ethene $\text{C}_2\text{H}_4$
$sp$ , two electron domains, as in ethyne $\text{C}_2\text{H}_2$

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

Carbon atoms with a $sp^{3}$ hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately $109.5\textdegree{}$
Carbon atoms with a $sp^{2}$ hybridization would demonstrate a triangular planar configuration with a bond angle of $120\textdegree{}$
Carbon atoms with a $sp$ hybridization would demonstrate a linear configuration with a bond angle of $180\textdegree{}$

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

$sp^{3}$ in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
$sp^{2}$ in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.

3 0

3 years ago