Answer: C)The smaller the soil particles, the more water and air available for plant growth.
Explanation:
Answer:
2.94
Explanation:
There is some info missing. I think this is the original question.
<em>A solution is prepared at 25 °C that is initially 0.38 M in chloroacetic acid (HCH₂ClCO₂), a weak acid with Ka= 1.3 x 10⁻³, and 0.44 M in sodium chloroacetate (NaCH₂CICO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
<em />
We have a buffer system formed by a weak acid (HCH₂ClCO₂) and its conjugate base (CH₂CICO₂⁻ coming from NaCH₂CICO₂). We can calculate the pH using the Henderson-Hasselbalch equation.
pH = pKa + log [CH₂CICO₂⁻]/[HCH₂ClCO₂]
pH = -log 1.3 x 10⁻³ + log (0.44 M/0.38 M)
pH = 2.94
Molarity = number of moles/Volume (L). Solve for the number of moles in the initial solution (3.78M = n/0.3 L) and then use that amount of moles and the new volume (0.5 L) to solve for the new Molarity.
Answer:
The answer is
<h2>0.07 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of metal = 5.11 g
volume = 71.46 mL
The density of the metal is
We have the final answer as
<h3>0.07 g/mL</h3>
Hope this helps you
