The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
Sodium borohydride is a relatively selective reducing agent Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.
The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
to learn more about sodium borohydride and ethanol click here ,
brainly.com/question/12955502
#SPJ4
Answer:
Double decomposition reaction
Explanation:
When hydrochloric acid reacts with any carbonates/hydrogen carbonates the products formed are metal chloride , water and carbon dioxide.Since HCl decomposes salts of weaker acids.
So the equation of the reaction between calcium carbonate and HCl is:
CaCO3+2HCl =CaCl2+H2O+CO2
This reaction is also known as double decomposition reaction.
Its an element Im pretty sure
Answer:
I dont undarsatnd 2gebwhsanKM<dwkdwndwkjdwnfwkjdnfkwnfwkf
Explanation:
wnkf mnf wnmd
