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LekaFEV [45]
3 years ago
5

How do you determine whether 2 figures are classified as congruent, similar, or neither?

Mathematics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

Congruent figures have the same proportions and have the exact dimensions as each other.

Similar figures have the same proportions but the dimensions are scaled.

If the figures don't satisfy either it is neither similar nor congruent.

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Name the congruent sides.
olga nikolaevna [1]
The answer is B.
Hope it helps!
4 0
3 years ago
Read 2 more answers
How many real number solutions are there to the equation 0=-3x^2 + x -4
natta225 [31]
We have that
<span>the equation
y=-3x</span>²<span> + x -4
the </span><span>real number solutions are the points x intercept of the graph
are the points when y=0

using a graph tool
see the attached figure

</span><span>the graph has no point of intersection with the x axis
</span>therefore

the answer is
there are zero real numbers solutions

8 0
2 years ago
What additional information do you need to prove triangle NOP = triangle QSR?
Wewaii [24]
After careful consideration i think I have an answer... 
So if you notice, These two triangles are a reflection of each other. 
Now even though these two triangles equal one another, we still have to consider the fact that they are different. (one side is the opposite of another)
So lets just name all the sides that equal each other. 
∠N = ∠Q
NO = QS
QR = NP
PO = SR
∠S = ∠O 
∠P = ∠R 

(by the way i'm going to be saying {the reflective side} every time i want to refer to the side with the two lines :P) - so bare with me. 

So therefore this would mean that ∠P = ∠S would be false, since one angle is from the side that is reflected and the other isn't. Makes sense?

So lets look over at the answers...

A.) PN = SQ 
For this answer choice, PN is on the non reflective side, while SQ is on the reflective side. Soooo... This answer choice is wrong. 

B.) NO = QR
NO  is part of the  unreflective side, while QR is part of the reflective side. 
Therefore this answer is wrong. They must be part of the same side. 

C.) ∠P = ∠S 
∠P is on the unreflective side, while angle ∠S is on the reflective side. 
There fore this answer is also wrong. 

D.) ∠O = ∠S 
Now ∠O is on the reflective side while ∠S is on the reflective as well. 
There fore this answer is correct . 

YOUR ANSWER IS. 
D.) ∠O = ∠S 

Good Luck! :)


6 0
3 years ago
Help again <br> álgebra 1
OLga [1]

Answer:

A (4,6)

ok im going to go through this step by step

4(4)=3(6)-2

16=18-2

16=16 (true solution)

18=3(4)+(6)

18=12+6

18=18 (true solution)

4 0
3 years ago
Let m = 7.
Zolol [24]
32 is the answer to the problem


4 0
2 years ago
Read 2 more answers
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