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just olya [345]
3 years ago
6

Solve each inequality: 14-6n<2(7-3n)

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

14 - 6n < 2(7 - 3n)

No Solution

0 < 0

work attached

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Ms. Garcia went shopping for a class celebration. Each bag of pretzels costs $3.49. She buys 3 bags of pretzels. Each container
Scilla [17]

Answer:

yes $ 18.85  Is the cost son$1.15 change

Step-by-step explanation:

3x3.49 = 10.47

2x4.19= 8.38  

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Find the percent of the number.<br> 20% of 60 is
exis [7]
"of" means to multiply.
20% * 60
= 0.2 * 60 (since % means divide by 100)
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What is the answer to 9×(6+7-3)-2​
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Answer:

88

Step-by-step explanation:

PEMDAS

9*(6+7-3)-2

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13-3=10

9*10-2

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Which of the following are solutions to the equation below?
Dovator [93]

Answer:

Apply quaratic equation

6 0
2 years ago
Suppose that the mean score on a creativity test is 16 and the standard deviation is 4. You are told that the distribution is no
Savatey [412]

Answer:

P(12

And we can find this probability on this way:

P(-1

We expect around 68.27% between the two scores provided.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(16,4)  

Where \mu=16 and \sigma=4

We are interested on this probability

P(12

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(12

And we can find this probability on this way:

P(-1

We expect around 68.27% between the two scores provided.

5 0
3 years ago
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