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Sloan [31]
3 years ago
12

Please help answer this​

Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Answer:

4.8 units^2

Step-by-step explanation:

Hello!  To find the area of this triangle, we need to know both the base and the height.  Neither is specifically given.  

We can find the height (CD) as follows:

3^2 - 1.8^2 = 5.76, so CD has the length sqrt(5.76) = 2.4.

Triangles ACD and ABC are similar.  Therefore, the following equatin of ratios holds:

1.8       CD       2.4

----- = ------- = --------

3.0      AB        AB

Then 1.8AB = 3.0(2.4), or AB = 7.2/1.8 = 4.

So the height of triangle ABC is 2.4 units and the length of the base is 4 units.

Therefore, the area of this triangle is A = (1/2)(base)(height), or

A = (1/2)(4 units)(2.4 units) = 4.8 units^2

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Francesca had 32 cups of flour. She used 3/8 of the flour for a recipe how much flour did Francesca used
cestrela7 [59]
She used 12 cups of flour.

Make a proportion to where 8/8 equals 32.
3/8 equals ?/32
Then cross multiply and divide.
32 x 3 = 96
96/8 = 12

You can also think of it like this. What number times 8 will get you 32?
Well that’s 4.
So 3 x 4 = 12
Since they are proportions of each other what the bottom is multiplied the top must be as well
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3 years ago
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Answer:1) 3

2) 0

3) I didnt quite understand this question...so I dont know its correct.

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Step-by-step explanation:


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Answer:

Therefore the Equation and missing value is

\dfrac{3}{4}=\dfrac{1}{6}+x      .............Equation for the Diagram

x=\dfrac{7}{12}

Step-by-step explanation:

Given:

Let Label the Diagram such that

AB =\dfrac{1}{6}

BC =c

AC =\dfrac{3}{4}

To Find:

Equation =?

x = ?

Solution:

Here Total Length is given in Two Parts

one\ part =\dfrac{1}{6}

Second\ part =x

Total =\dfrac{3}{4}

For a Line A-B-C

AC =AB+BC       ..............Line Addition Property

Substituting the values we get

\dfrac{3}{4}=\dfrac{1}{6}+x ...Equation for the Diagram

x = \dfrac{3}{4}-\dfrac{1}{6}\\\\x=\dfrac{18-4}{4\times 6}\\\\x=\dfrac{14}{24}\\\\x=\dfrac{7}{12}

Therefore the Equation and missing value is

\dfrac{3}{4}=\dfrac{1}{6}+x ...Equation for the Diagram

x=\dfrac{7}{12}

3 0
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