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Gelneren [198K]

3 years ago

14

what is the final speed of an object that starts from rest and accelerates uniformly at 4.0 meters per second over a distance of

8.0 meters

1 answer:

sladkih [1.3K]3 years ago

5 0

The final speed would be 8.0 m/s

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Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t

marin [14]

Answer:

Part a)

$Q = 952 cal/day$

Part b)

$P = 46 Watt$

Part c)

$\Delta P = 54 W$

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

$m = 5000 kg$

$Q = 70,000 Cal$

so we have energy required per kg

$E = \frac{70,000}{5000}$

$E = 14 cal/kg$

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

$Q = 68 \times 14$

$Q = 952 cal/day$

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

$P = \frac{952 \times 4186}{24\times 3600}$

$P = 46 Watt$

Part c)

resting power given in the book is

$P' = 100 W$

so this is less than the power given

$\Delta P = 100 - 46$

$\Delta P = 54 W$

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When looking at liquids in a container, that have layered on one another;

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What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?

laila [671]

Answer:

Work done, W = 750 joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

It moves to a distance of, d = 15 meters

We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,

$W=F\times d$

$W=50\ N\times 15\ m$

W = 750 joules

So, the work done on an object is 750 joules. Hence, this is the required solution.

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3 years ago