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Gelneren [198K]
3 years ago
14

what is the final speed of an object that starts from rest and accelerates uniformly at 4.0 meters per second over a distance of

8.0 meters
Physics
1 answer:
sladkih [1.3K]3 years ago
5 0
The final speed would be 8.0 m/s
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A leaf is floating on the Surface of the water,what will happen to its movement? Explain
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Answer:

MRCORRECT has answered the question

Explanation:

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What type of configuration is used in the HEVs available in the US today?
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(c) Due to up thrust
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3 years ago
An electron emitted in the beta decay of bismuth-210 has a mean kinetic energy of 390 keV. (a) Find the de Broglie wavelength of
Sauron [17]

Explanation:

Given that,

The mean kinetic energy of the emitted electron, E=390\ keV=390\times 10^3\ eV

(a) The relation between the kinetic energy and the De Broglie wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2meE}}

\lambda=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 390\times 10^3}}

\lambda=1.96\times 10^{-12}\ m

(b) According to Bragg's law,

n\lambda=2d\ sin\theta

n = 1

For nickel, d=0.092\times 10^{-9}\ m

\theta=sin^{-1}(\dfrac{\lambda}{2d})

\theta=sin^{-1}(\dfrac{1.96\times 10^{-12}}{2\times 0.092\times 10^{-9}})

\theta=0.010^{\circ}

As the angle made is very small, so such an electron is not useful in a Davisson-Germer type scattering experiment.

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3 years ago
A certain heat engine takes in 300 J of energy from a hot source and then transfers 200 J of that energy to a colder object. Wha
Greeley [361]

Answer:

The efficiency is 0.33, or 33%.

Explanation:

From the thermodynamics equations, we know that the formula for the efficiency of a heat engine is:

\eta=1-\frac{Q_2}{Q_1}

Where η is the efficiency of the engine, Q_1 is the heat energy taken from the hot source and Q_2 is the heat energy given to the cold object. So, plugging the given values in the formula, we obtain:

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This means that the efficiency of the heat engine is 0.33, or 33% (The efficiency of an engine is dimensionless).

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