3 years ago

What is the average power output (in W) of a heart defibrillator that dissipates 435 J of energy in 10.5 ms?

Physics

1 answer:

Yuki888 [10]3 years ago

7 0

Answer:

The power is $P = 41429 \ W$

Explanation:

From the question we are told that

The energy is $E = 435 \ J$

The time taken is $t = 10.5 \ ms = 10.5 *10^{-3} \ s$

Generally the the average power is mathematically represented as

$P = \frac{E}{t}$

=> $P = \frac{ 435}{ 10.5*10^{-3}}$

=> $P = 41429 \ W$

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If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a

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W = 289.70 kg

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