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Pani-rosa [81]
3 years ago
8

Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find

it easier to push the box on the marble floor than on the carpeted floor?
A. The box experience more friction on the carpeted floor
B. The box experience less friction on the carpet floor
C. The box experiences more applied force on the marble floor
D. The box experiences less normal force on the marble floor
Physics
2 answers:
FinnZ [79.3K]3 years ago
4 0
Answer A is correct because the carpet usually enforces more friction. The marble carpet is smoother, thus there is less friction
AysviL [449]3 years ago
3 0

Answer:

A. The box experiences more friction on the carpeted floor

Explanation:

Friction is the force that opposes the motion of an object when it slides along a surface. The magnitude of the friction is given by

F=\mu mg

where m is the mass of the object, g is the acceleration due to gravity, and \mu is the coefficient of friction, which depends on the type of material of the surface: the larger this coefficient, the stronger the friction, the more difficult is to push the box along the surface. Generally, a smooth surface has a lower coefficient of friction, while a rough surface has a larger coefficient of friction.

In this case, Ethan find it easier to push the box on the marble floor, because marble is smoother than the carpet and so friction is weaker, while for the carpeted floor the coefficient of friction is larger and so the friction is stronger, making it more difficult to push the box.

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PLEASE HELP!!!!
defon

Answer:

v = 2.45 m/s

Explanation:

first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:

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8 0
3 years ago
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Answer:

a)3.5s

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c)34.33m/S

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Explanation:

Hello!

we will solve this exercise numeral by numeral

a) to find the time the ball takes in the air we must consider that vertically the ball experiences a movement with constant acceleration whose value is gravity (9.81m / S ^ 2), that the initial vertical velocity is zero, we use the following equation for a body that moves with constant acceleration

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y = height=60m

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T=3.5s

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c)

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