Hi, Hayesannaliese! There are two ways of solving this.
For right triangles, we can use the Pythagorean theorem. For this, we can see that (-2, 5) is 9 units above (-2, -4) and (6, 5) is 8 units right of (-2, 5). For the Pythagorean theorem,
. Plug in the a and b values below:

--> 
---> 
----> 
c = 12.04 units
Second method: finding the distance between two points

For this problem, we need to find the distance between (-2, -4) and (6, 5).
So the equation is 
--> 
---> 
----> 
= 12.04 units.
Hope this was helpful. Good luck. :)