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givi [52]
3 years ago
7

Please help me with these questions!!! will give you brainliest.

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Hi, Hayesannaliese! There are two ways of solving this.

For right triangles, we can use the Pythagorean theorem. For this, we can see that (-2, 5) is 9 units above (-2, -4) and (6, 5) is 8 units right of (-2, 5). For the Pythagorean theorem, a^2 + b^2 = c^2. Plug in the a and b values below:

(8)^2 + (9)^2 = c^2

--> 64 + 81 = c^2

---> 145 = c^2

----> \sqrt{145} = c

c = 12.04 units


Second method: finding the distance between two points

\sqrt{(x2 - x1)^2 + (y2 - y1)^2}

For this problem, we need to find the distance between (-2, -4) and (6, 5).

So the equation is \sqrt{(6 - (-2))^2 + (5 - (-4))^2}

--> \sqrt{8^2 + 9^2}

---> \sqrt{64 + 81}

----> \sqrt{145}

= 12.04 units.

Hope this was helpful. Good luck. :)

n200080 [17]3 years ago
6 0
Apply Pythagorean:
Hypotenuse^2 = 8^2 + 9^2
Hypotenuse = sqrt ( 64+81)
Hypotenuse = sqrt 145
Hypotenuse ~ 12.04
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Answer:

A ; 23rd century

Step-by-step explanation:

Here, we want to select which of the options is next to have a descending year.

Since all are in the same century i.e 20-something, we do not have an issue with the first digit.

What we need to work on is the last three digits;

We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.

The most recent of all these is the year 2210, so what century does this belong?

Kindly note that, the years 2001-2100 belong to the 21st century.

The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century

The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century

8 0
3 years ago
According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

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Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

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s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0
3 years ago
Round 2. 873 to the nearest tenth
PtichkaEL [24]
2.873 ≈2.9 (nearest tenth)
6 0
3 years ago
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The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?​
horsena [70]

Step-by-step explanation:

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Subtracting equation (2) from equation (1)

a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\

Substituting d = - 3 in equation (1), we find:

a + 9\times (-3)= - 27\\\\\therefore a - 27 = - 27\\\\\therefore a  = 27- 27\\\\\huge \red {\boxed {\therefore a  = 0}}\\\\

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3 0
3 years ago
Negative three plus x equals eleven
skad [1K]
-3 + x = 11
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3 years ago
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