Answer:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Step-by-step explanation:
For this case we can estimate the population proportion of people that they did work at home at least once per week with this formula:

We need to find the critical value using the normal standard distribution the z distribution. Since our condifence interval is at 99%, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Answer:
220
Step-by-step explanation:
Answer:
39858075
Step-by-step explanation:
Hello,
One basic way to see it is to compute the values.
75 = 25 * 3
225 = 75 * 3
675 = 225 * 3
etc ...
We can notice that this is multiplied by 3 every 10 years so we can compute as below.
year population
1970 25
1980 75
1990 225
2000 675
2010 2025
2020 6075
2030 18225
2040 54675
2050 164025
2060 492075
2070 1476225
2080 4428675
2090 13286025
2100 39858075
So the correct answer is 39858075
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
noooooooo
Step-by-step explanation: