8 bc 2/3 x 18= 12 and 12-4 = 8 :) sorry if im wrong tho
Answer:
3
Step-by-step explanation:
2(x + 1) = 3(5 - x) + 2
Distribute,
2(x + 1) = 3(5 - x) + 2
2x + 2 = 3(5 - x) + 2
Rearrange terms,
2x + 2 = 3(5 - x) + 2
2x + 2 = 3(-x + 5) + 2
Distribute,
2x + 2 = 3(-x + 5) + 2
2x + 2 = -3x + 15 + 2
Add the numbers,
2x + 2 = -3x + 15 + 2
2x + 2 = -3x + 17
Subtract 2 from both sides,
2x + 2 = -3x + 17
2x + 2 - 2 = -3x + 17 - 2
2x = -3x + 17 - 2
2x = -3x + 15
Add 3x to both sides,
2x = -3x + 15
2x + 3x = -3x + 3x + 15
5x = -3x + 3x + 15
5x = 15
Divide both sides by the same factor (15),
5x = 15
5x/5 = 15/5
x = 15/5
x = 3
Hence, the answer is 3.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The solution is 
Step-by-step explanation:
From the question we are told that

and 
Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as
![| \frac{\delta (x,y)}{\delta (u, v)} | = | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |](https://tex.z-dn.net/?f=%7C%20%5Cfrac%7B%5Cdelta%20%20%28x%2Cy%29%7D%7B%5Cdelta%20%28u%2C%20v%29%7D%20%7C%20%3D%20%20%7C%20%5C%20det%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%5Cfrac%7B%5Cdelta%20x%7D%7B%5Cdelta%20u%7D%20%7D%26%7B%5Cfrac%7B%5Cdelta%20x%7D%7B%5Cdelta%20v%7D%20%7D%5C%5C%5Cfrac%7B%5Cdelta%20y%7D%7B%5Cdelta%20u%7D%26%5Cfrac%7B%5Cdelta%20y%7D%7B%5Cdelta%20v%7D%5Cend%7Barray%7D%5Cright%5D%20%7C)
![= |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right] |](https://tex.z-dn.net/?f=%3D%20%7C%5C%20det%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-2e%5E%7B-2u%7D%20cos%285v%29%7D%26%7B-5e%5E%7B-2u%7D%20sin%285v%29%7D%5C%5C%7B-2e%5E%7B-2u%7D%20sin%285v%29%7D%26%7B-2e%5E%7B-2u%7D%20cos%285v%29%7D%5Cend%7Barray%7D%5Cright%5D%20%20%7C)

So
![\frac{\delta (x,y)}{\delta (u, v)} | = |det \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20%20%28x%2Cy%29%7D%7B%5Cdelta%20%28u%2C%20v%29%7D%20%7C%20%3D%20%7Cdet%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7C)
=> 
substituting for a, b, c,d
=> 
=> 
=> 
Suppose x quarts of the 50% solution
0.5x+0.2*20=0.4(x+20)
0.5x+4=0.4x+8
0.1x=4
x=40
2*&/45/+=67364/3/4/32:5,6544 is hothead answer