Answer:
Given the statement: if y =3x+6.
Find the minimum value of 
Let f(x) =
Substitute the value of y ;
Distribute the terms;
The derivative value of f(x) with respect to x.
Using 
we have;
Set 
then;
By zero product property;
and 2x + 3 = 0
⇒ x=0 and x = 
then;
at x = 0
f(0) = 0
and
x = -1.5
Hence the minimum value of is, -5.0625
Y = 2/7x - 4
y + 4 = 2/7x
4 = 2/7x - y (multiply everything by seven to get rid of the fraction)
28 = 2x - 7y
2x - 7y = 28
Answer:
74
Step-by-step explanation:
45-45+56=56 XX_BoxercarnXXJay is my roblox username if you want to be friends
First, let's convert each line to slope-intercept form to better see the slopes.
Isolate the y variable for each equation.
2x + 6y = -12
Subtract 2x from both sides.
6y = -12 - 2x
Divide both sides by 6.
y = -2 - 1/3x
Rearrange.
y = -1/3x - 2
Line b:
2y = 3x - 10
Divide both sides by 2.
y = 1.5x - 5
Line c:
3x - 2y = -4
Add 2y to both sides.
3x = -4 + 2y
Add 4 to both sides.
2y = 3x + 4
Divide both sides by 2.
y = 1.5x + 2
Now, let's compare our new equations:
Line a: y = -1/3x - 2
Line b: y = 1.5x - 5
Line c: y = 1.5x + 2
Now, the rule for parallel and perpendicular lines is as follows:
For two lines to be parallel, they must have equal slopes.
For two lines to be perpendicular, one must have the negative reciprocal of the other.
In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.
However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.
<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
