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Sliva [168]
3 years ago
10

find the average rate of change from t=2 to t=5 for the velocity function v(t)=t^2-t+10. WILL GIVE THE BRAINLIEST ANSWER--EXPLAI

N!!
Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0
Answer: The average rate of change is 6.
First, plug in each value of <em>t</em> into the function, v(t) to find there coordinate pairs.

v(2) = (2)^2 - (2) + 10
v(2) = 4 + 8
v(2) = 12

v(5) = (5)^2 - (5) + 10
v(5) = 25 + 5
v(5) = 30

You can write these values as coordinate pairs, like so: (2, 12) and (5, 30).
The formula for the average rate of change is A(x) =  \frac{f(x)-(f(a)}{x-a}. When you plug in the values from this particular case, the average rate of change formula becomes A(t) = \frac{30-12}{5-2}, or A(t)= \frac{18}{3}.

Looking at the equation, you can solve for the average rate of change between t = 2 and t = 5, which equals 6.
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Step-by-step explanation:

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4 0
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2 years ago
The ratio of boys to girls in the sixth grade are 2:3. If there are 200 sixth graders, how many of them are boys?
Likurg_2 [28]

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3 0
3 years ago
What is the total area of the shape?<br><br> A 35 cm?<br> B 100 cm?<br> C 70 cm?<br> D 50 cm?
Vesnalui [34]

Answer:

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Step-by-step explanation:

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30 + 40 = 70

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Have a good day :)

4 0
3 years ago
Read 2 more answers
What is the rate of change of the linear function that passes through the points (1, 0) and (0, -3)
melisa1 [442]

Answer:

3

Step-by-step explanation:

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A = (-3 - 0) / (0 - 1) = -3 / -1 = 3

:)

6 0
2 years ago
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