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Cloud [144]
3 years ago
11

A typical sugar cube has an edge length of 1 cm. if you had a cubical box that contained a mole of sugar cubes, what would its e

dge length be? (one mo
Mathematics
1 answer:
timama [110]3 years ago
8 0
1mol=6.02*10^23 units or something


so that is the volume
v=side^3

6.02*10^23=side^3
cube root both sides
∛6.02*(10^(23/3))≈8.44369*10^7

so the edge length would be about 84436877.3356756850163167551031 inches per side

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a gold bar weighs 12.6 kg. if there are 0.45 kilograms in 1 pound, then how much does the gold bar weigh in pounds?
k0ka [10]

Answer:

28pounds

Step-by-step explanation:

0.45=1pound

12.6

12.6/0.45=28pounds

7 0
3 years ago
Read 2 more answers
Ryan buys a bag of cookies that contains 8 chocolate chip cookies, 4 peanut butter cookies, 4 sugar
Pavlova-9 [17]

Answer:

4/69 to be exact. Slightly greater than 1/18

Step-by-step explanation:

The chance of selecting the PB cookie on the first try is 4 out of 24 or 1 out of 6. There are now 23 coolies left; 8 are chocolate, so 8/23 chance. (Slightly greater than 1/3) The chance of both events happening is the product if the individual events' chances. So multiply 1/6 times 8/23 to get 8/138. That reduces to 4/ 69. If he had put that first cookie back, the multiplication would have been 1/6×1/3. A lot easier.

4 0
3 years ago
Plz answer with work
V125BC [204]

Answer:

Calculate 93% of 29.96.

Your final answer is approximately 27.86

6 0
2 years ago
PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE
Debora [2.8K]

Problem 1

<h3>Answer:  6.7</h3>

----------------

Work Shown:

The two points are (x_1,y_1) = (1,-2)  and (x_2,y_2) = (4,4)

Apply the distance formula to get the following

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer:  3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points (x_1,y_1) = (3,1) and (x_2,y_2) = (5,-2)

The distance between them is...

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\

This distance is approximate.

5 0
3 years ago
What is the base area ??
mamaluj [8]
the answer to your question for a base area is 100
6 0
3 years ago
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