What is the base area ??

The radius of a circle is decreasing at a constant rate of 0.1 centimeter per second. In terms of the circumference C, what is t

valentinak56 [21]

Answer:

lol its a little difficult for me but the answer is B

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP Which expression represents the difference quotient of the function f (x) = negative StartRoot 2 x EndRoot?

natali 33 [55]

Answer:

c is the correct option

Step-by-step explanation:

from,

f'(x) = h >0 f(x + h) - f(x)

h

f(x) = - √2x

f(x + h) = - √(2x + h)

f'(x) = h>0 -√(2x + h) - √2x

h

rationalize the denominator

= h>0 -√(2x + h) + √2x (-√(2x + h) - √2x)

h (-√(2x + h) - √2x)

= h>0 4x + 2h - 4x

h(-√(2x + h) -√2x)

= h>0 2h

h(-√(2x+h) - √2x)

= h>0  2 

-√(2x+h) - √2x

5 0

3 years ago

Read 2 more answers

Haruka hiked several kilometers in the morning. She only hiked 6 kilometer in the afternoon, which was 25% less she had hiked in

Marrrta [24]

7.5 kilometers is what she hiked

3 0

3 years ago

Addidas wants Kanye West to give a speech at a shoe event. Addidas is offering Kanye $500. How much does he want?

krok68 [10]

Answer:

that's the price of one shoeee, XD kanye want $500,000

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

7 0

4 years ago