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3 years ago

What quadratic has roots x=8 and x= -5

Mathematics

1 answer:

Alona [7]3 years ago

5 0

Answer:

So the correct option is X squared -3 X +40

Step-by-step explanation:

If a polynomial has roots x=8 and x=-5, then we know that the factorized form is:

(x-8)(x+5)

So, to find the polynomial we need to expand the polynomials:

(x-8)(x+5) = (x^2 +5x - 8x + 40) = x^2 -3x + 40

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$28,000 invested at a rate of 4% compounded annually; 5 years

sasho [114]

$28<span> compounded on a </span>Yearly<span> basis over the course of </span>5<span> years at a </span>4% interest rate would be worth:

<span>$34</span>

4 0

3 years ago

Read 2 more answers

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

4 years ago

When 5 is added to a set of 3 numbers the mean increases to 4.6. What was the mean of the original 3 numbers?

SVEN [57.7K]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Multiply 4.6 by 4 to get the sum of the numbers after 5 was added:

4.6 x 4 = 18.4

^ This is the new total

Subtract 5 from this:

18.4 - 5 = 13.4

Divide this value by 3 to get the original mean:

13.4/3 = 67/15

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago

A⁴×a²<br>answer question below please

Softa [21]

Step-by-step explanation:

•a⁴×a²

•a⁴+²

•a^6

I hope it will help you....

<h3>MARK ME BRAINLIEST...</h3>

3 0

3 years ago

Read 2 more answers

A gallon of milk cost $2.90 in 2002. In 2018, it cost

lutik1710 [3]

Answer:

<em>The cost of a gallon of milk changed 31%</em>

Step-by-step explanation:

<u>Percent Change</u>

Is the difference between two values of the same variable in different times or conditions, expressed as a percentage of the original value.

The formula is:

$\displaystyle Pc=\left |\frac{v1-v2}{v1} \right |\cdot 100\%$

Where

v1 = original value

v2 = final value

The gallon of milk cost v1=$2.90 in 2002 and v2=$3.80 in 2018. The percent change is:

$\displaystyle Pc=\left |\frac{2.90-3.80}{2.90} \right |\cdot 100\%$

$\displaystyle Pc=\left |\frac{-0.9}{2.90} \right |\cdot 100\%$

Pc = 31%

The cost of a gallon of milk changed 31%

8 0

3 years ago