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miskamm [114]
3 years ago
12

How are inderect measurements useful

Mathematics
1 answer:
likoan [24]3 years ago
8 0
Indirect measurements are useful when it is not possible to measure the object. For some reason. Scientists use indirect measurements when the measure the, temperature of a flame my measuring the wavelength of the light being given off
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This is the question: -10.7 + (- 3.5 )
Inessa [10]

Answer:

the answer is -14.2

Step-by-step explanation:

-10.7 + (-3.5)= -14.2

8 0
3 years ago
Read 2 more answers
1.Write an equation of the line in point-slope
Oduvanchick [21]

Answer:

<u>Point slope form</u>

y-10 = -6 (x+1)

<u>Slope-intercept form</u>

y=-6x+4

<u>Standard form</u>

4x+y=4

Step-by-step explanation:

Equation in Point slope form is

y-y_1=m (x-x_1) ---------- (1)

Here

m=-5 \ \ \ and \ \ \ (x_1, y_1) = (-1, 10)

Substituting values in equation (1)

y-10 = -6 (x+1) ------------- (2)

Equation (2) is equation of line in point slope form.

<u>Re-arranging equation (2)</u>

y = -6x - 6 + 10

y=-6x+4 ----------- (3)

Equation (3) is equation of straight line in slope-intercept form

<u>Re-arranging equation (3)</u>

<u />4x+y=4   --------(4)

Equation (4) is equation of line in standard form

6 0
2 years ago
Solve for x.<br><br> -5x = -10
andreev551 [17]

Answer:

x=2

Step-by-step explanation:

divide -5 to both sides to isolate the x. two negatives make a positive therefore x=2.

i hope this helps :)

6 0
2 years ago
Read 2 more answers
A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

5 0
3 years ago
Simplify<br> 10+6/2+3<br> i don’t understand
labwork [276]

Answer:

16/6 = 2 4/6 = 2 2/3

Step-by-step explanation:

the answer is two and two thirds  assuming that this is a fraction :)

7 0
2 years ago
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