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3 years ago

A good way to decrease the strength of a magnet is to what?

1 answer:

6 0

-- drop it on the floor; -- hit it with a hammer; -- heat it red hot in a flame; -- wrap many turns of wire around it and pass a high AC current through the wire.

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Which is the best example of muscular endurance

enot [183]

Answer:

The Top 5 Muscular Endurance Exercises

Plank.

Body weight squats.

Walking lunges.

Pushups.

Situps

Explanation: To do these exercises you must sustain your muscles for a long time. The more you endure it, the more muscular endurance you have.

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3 years ago

Read 2 more answers

22= 1/2 9.8 t^2

djverab [1.8K]

Answer:

5790 i dony kiow

Explanation:

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3 years ago

When conducting an experiment, a scientist should:?

podryga [215]

There are many things you have to do but a quick run down would be keep notes, share their information, take many tests, always be safe when testing something, etc.

7 0

4 years ago

Read 2 more answers

A 770-kg boulder is raised from a quarry 106 m deep by a long uniform chain having a mass of 575 kg . This chain is of uniform s

Bas_tet [7]

Answer:

(a) $a_{y}= 1.931m/s^{2}$

(b) $t=10.478s$

Explanation:

For Part(a)

Apply ∑Fy=ma

$T-Mg=Ma_{y} \\$

Solve for a

$a_{y}=\frac{T-Mg}{M}=\frac{2.80mg-Mg}{M} \\a_{y}=\frac{(2.80*575kg-1345kg)}{1345kg}*(9.80m/s^{2} )\\a_{y}= 1.931m/s^{2}$

For Part(b)

Assume the maximum acceleration (maximum tension upwards is greater than the weight of the chain+boulder)

As the given data

$a_{y}=1.931m/s^{2}\\ y-y_{o}=106m\\v_{oy}=0$

Using equation of simple motion

$y-y_{o}=v_{oy}t+(1/2)a_{y}t^{2} \\t=\sqrt{\frac{2(y-y_{o})}{a_{y}} }\\ t=\sqrt{\frac{2(106m)}{1.931m/s^{2} } }\\t=10.478s$

4 0

4 years ago

A ball is thrown straight up at 20 m. What is the balls velocity as it hits the ground?

deff fn [24]

Answer:

The velocity of the ball as it hit the ground = 19.799 m/s

Explanation:

Velocity: Velocity of a body can be defined as the rate of change of displacement of the body. The S.I unit of velocity is m/s. velocity is expressed in one of newtons equation of motion, and is given below.

v² = u² + 2gs.......................... Equation 1

Where v = the final velocity of the ball, g = acceleration due to gravity, s = the height of the ball

Given: s = 20 m, u = 0 m/s

Constant: g = 9.8 m/s²

Substituting these values into equation 1,

v² = 0 + 2×9.8×20

v² = 392

v = √392

v = 19.799 m/s.

Therefore the velocity of the ball as it hit the ground = 19.799 m/s

5 0

4 years ago