Answer:
a.The 60 km/HR car
Explanation:
Kinetic Energy: This can be defined as the energy of a body due to motion. The S.I unit of kinetic energy is Joules (J).
It can be expressed mathematically as
Ek = 1/2mv²......................... Equation 1
Where Ek = kinetic energy, m = mass, v = velocity.
(i) A car travelling at 30 km/hr, with a mass of m,
Ek = 1/2(m)(30)²
Ek = 450m J.
(ii) A car travelling at 60 km/hr, with a mass of m/2
Ek = 1/2(m/2)(60)²
Ek = 900m J.
Thus , the car travelling at 60 km/hr at half mass has a greater kinetic energy to the car traveling at 30 km/hr at full mass.
The right option is a.The 60 km/HR car
Answer: learn how to do it on your own idiot
Explanation: try hard in school
Answer:
Explanation:
Hi!
In order to obtain the Lagrangian of the system we must first write the Kinetic and Potential Energies. Lets orient our axes such that the axis of the cone coincide with the z axis. In cilindrical coordinates we have
- (1)
But, since the particle is constrained to move on the surface of the cilinder, we have the following relation between r and z:
or:
- (2)
and:
replacing (2) in (1) we obtain:
- (3)
Now the kinetic energy is given as:
- (4)
And the potential energy is given by:
So the Langrangian is given by:
And the equations of motion are:
For θ
For r
Obtained from the Euler-Langrange equations
Here the conserved quantity is given by the first equation of motion, namely:
Which is the magnitude of the angular momentum
Answer: C
Explanation:
Calculate EkA -kinetic energy of car A
m=1000kg
Va=16.66 m/s
EkA=m*Va²/2
Eka=(1000kg*277.556m²/s²)/2
Eka=138 777.8 J
Calculate kinetic energy of CarB:
m=2000 kg
Vb=8.33 m/s
Ekb=(m*Vb²)/2
Ekb=(2000kg*69.39m²/s²)/2
Ekb=69 388.9 J
compare Eka with EkB
Eka/Ekb=138 777.8 J/69 388.9
Eka/Ekb=2
Answer: C
produces as much as or more energy than it uses
Explanation:
This implies that the total energy used by the building is equivalent to the energy generated by the site