A simple circuit consists of a light bulb connected to the terminals of a battery. A voltmeter shows a potential difference of 1

Question

3 years ago

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A simple circuit consists of a light bulb connected to the terminals of a battery. A voltmeter shows a potential difference of 1

8.5 V across the light bulb, whereas an ammeter registers a current of 0.485 A in the circuit. Determine the resistance of the bulb.

Physics

1 answer:

larisa [96] · Answer 1 · 2022-07-02T02:26:07+03:00

<h2>Answer:</h2>

38.14Ω

<h2>Explanation:</h2>

Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;

V = I R -------------------(i)

<em>Where</em>;

R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)

<em>From the question;</em>

V = 18.5V

I = 0.485A

<em>Substitute these values into equation (i) as follows;</em>

18.5 = 0.485 x R

<em>Solve for R;</em>

R = 18.5 / 0.485

R = 38.14Ω

Therefore the resistance of the bulb is 38.14Ω