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3 years ago

Mathphys please notice me

Physics

2 answers:

eimsori [14]3 years ago

7 0

Answer:

24.2 s

29.2 m

Explanation:

First, convert each speed from km/h to m/s.

91.5 km/h = 25.42 m/s

77.5 km/h = 21.53 m/s

The speed of the cheetah relative to the gazelle is:

v = 25.42 m/s − 21.53 m/s

v = 3.89 m/s

So the time it takes for the cheetah to catch the gazelle is:

x = v t

94.2 m = (3.89 m/s) t

t = 24.2 s

If instead we want to find x so that t = 7.5 s, then:

x = v t

x = (3.89 m/s) (7.5 s)

x = 29.2 m

Marianna [84]3 years ago

3 0

Answer:

24.2 s

29.2 m

Explanation:

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2 years ago

If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add

mr Goodwill [35]

Each $Al^+^3$ ion contains three extra protons. Hence, the extra charge on each $Al^+^3$ = $3 \times 1.6 \times 10^-^1^9$ C

Total charge = 0.035 pC

Total charge (Q) = $0.035 \times 10^-^1^2$ C

Let the number of $Al^+^3$ ions be n.

According to question:

$n \times 3 \times 1.6 \times 10^-^1^9 =0.035 \times 10^-^1^2$

$n = \frac{0.035 \times 10^-^1^2}{3 \times 1.6 \times 10^-^1^9}$

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n = 72917

Hence, the total number of ions needed to be transferred is 72917

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3 years ago

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2 years ago

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Taya2010 [7]

Answer:

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2 years ago

A uniform 2.50m ladder of mass 7.30kg is leaning against a vertical wall while making an angle of 51.0degree with the floor. A w

Zigmanuir [339]

Answer:

19.95 J

Explanation:

The center of mass of the ladder is initially at a height of:

$h_1=\frac{L}{2}sin\theta$

The center of mass of the ladder ends at a height of:

$h_2= \frac{L}{2}sin90$ =L/2

So, the work done is equal to the change in potential energy which is:

W = PE = $mg(h_2-h_1)$

now $h_2-h_1= 1-sin\theta$

therefore

W = [mgL/2]×[1 - sin(theta)]

W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]

solving this we get

W = 19.95 J

8 0

2 years ago