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lara31 [8.8K]
3 years ago
6

The science that includes the study of tumor cells, macrophages and protein synthesis is called

Biology
2 answers:
lidiya [134]3 years ago
6 0

The science that includes the study of tumor cells, macrophages and protein synthesis is cell biology.This is because all the three thing given in the question denotes towards the study of cells.

Study of structure and function of cell. Knowing all about the diseases associated with the cell function. Any complication during protein synthesis can led to production of any non functional protein.

Any defect in the cell structure can cause disease and this can be known only when the study of cell structure and function is done.

GalinKa [24]3 years ago
5 0

The science of Cancer Biology focuses on the study of the different mechanisms and fundamental process of cell growth, the transformation of normal to cancer cells, and the metastasis or spread of these cancer cells to other parts of the body.  


As such, it includes the study of how tumor cells develop and grow. It also includes studying how the immune system responds to cancer cells, thus including macrophages and their response to the presence of pathogens and cancer cells.  Underlying all these is the inclusion of a study on protein synthesis as it is the process where biological cells build and create new specific proteins in the body.



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List the functions of proteins in the text area below.
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There are 100 cats in a population that follows hardy-weinberg conditions. 4 cats display a recessive white coat color. how many
mr Goodwill [35]

We know that Hardy-Weinberg conditions include the following equations:


p^{2}+2pq+ q^{2}=1


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And where p = dominant, and q = recessive; this means that p^{2} is equal to the homozygous dominant, 2pq is the heterozygous, and q^{2} is the homozygous recessive .


So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of \frac{4}{100} or 0.04. Let that equal our q^{2} value.


So when we solve for q, we get:


q^{2}=0.04

q=\sqrt{0.04} =0.2


Now that we have our q value, we can use the other equation to find p:


p+q=1


p+0.2=1


p=0.8


So then we can solve for our heterozygous population:


2pq=2(0.8)(0.2)=0.32


This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:


0.32*100=32cats


So now we know that there are 32 heterozygous cats in the population.

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Answer:

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Explanation:

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