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boyakko [2]
3 years ago
6

A plant starts out at 12 inches tall and grows 1 inch per week . Write an equation for this situation. What is the slope ? Is th

e slope continuous or discrete ? Explain.
Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

h(t) = 12 inches + (1 inch/week)t; continuous

Step-by-step explanation:

This situation can be described with a linear function.  The initial value of the plant height is 12 inches, and the weekly growth is 1 inch/week.

Thus, if h(t) represents the plant height at the end of the t-th week,

h(t) = 12 inches + (1 inch/week)t

The slope is 1 inch/week, and is continuous, since plan growth is continuous.

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(8r + 5) - (3r + 5)<br><br> help a sista out &lt;3
Rufina [12.5K]

Answer:

5r

Step-by-step explanation:

(8r + 5) - (3r + 5)

8r + 5 - 3r - 5

5r

8 0
3 years ago
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un
WINSTONCH [101]

Answer:

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

\bar X_{1}=5135 represent the mean for four year college

\bar X_{2}=4436 represent the mean for two year college

s_{1}=783 represent the sample standard deviation for four year college

s_{2}=553 represent the sample standard deviation two year college

n_{1}=35 sample size for the group four year college

n_{2}=35 sample size for the group two year college

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

6 0
3 years ago
Please help!!!!!!!!!
shepuryov [24]
A, the first one only, this parabola only has a minimum and no maximum.  the other statements are also just false 
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3 years ago
Please help!!!!!!!!!!!!!!!!!!!!
Shtirlitz [24]
The believe the answer. is A. Have a good day.
7 0
3 years ago
Read 2 more answers
Which of the Venn diagrams represents “not X”?
Dvinal [7]

Answer:

The green zone in the image provided below

Step-by-step explanation:

<u>Venn Diagrams</u>

They are graphic representations of the relations between different sets. Each set (X for example), is represented as an oval, rectangle or any other closed figure. The inside area of that figure are the elements who belong to X. The outside of that figure is "not X", or the logical negation of X

This question doesn't provide any references or options to answer it, but I'm giving you some general content to help you with your particular case. Please find the relevant information in the image below.

It can be seen the set called X, another one called Y and the sample space called \Omega. Everything inside the oval X belongs to it, everything outside the oval X is NOT X, shown in green.

3 0
3 years ago
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