7/8=?/48<br> A.42<br> B.13<br> C.1<br> D.6

A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building. If the top of the ladder sl

algol [13]

Answer:

As per the statement:

A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building.

⇒Length of the ladder against a building = 25 foot

and Length of the bottom of the ladder from the building= 7 feet.

You had Before the slip.

Let x be the height of the building where ladder hits the building

By Pythagoras theorem:

$\text{Hypotenuse side}^2=\text{Perpendicular}^2+\text{Base}^2$

Here, Perpendicular side = Height of the building = x , Base = Length of the bottom of the ladder from the building = 7 foot and Hypotenuse side = 25 foot

Substitute the value to solve for x;

$25^2=x^2+7^2$

$625=x^2+49$

or

$x^2 = 625-49 = 576$

$x = \sqrt{576} = 24$ foot.

⇒Height of the building = 24 foot

Now, if the ladder slips down 4 feet.

You had after slip

⇒Now, the height of the building becomes = 24-4 = 20 foot.

Let y be the distance from the building wall

then by Pythagoras theorem;

$y^2+20^2 = 25^2$

$y^2+400 =625$

$y^2 = 625-400 = 225$

$y=\sqrt{225} = 15$ foot.

We have to find how many feet will the bottom slide out.

Since, Originally the distance of the bottom from the building = 7 foot

And now, the distance is = 15 foot.

The bottom slide out will be = 15 - 7 =8 foot

Therefore, 8 feet will the bottom slide out

6 0

3 years ago

PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work

pentagon [3]

Answer:

c This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

a. 9/3 =3

2/7 does not =3 so this is not a direct variation

b 1/2 = .5

-3/6 = -.5

This is not the same so this is not a direct variation

c. 27/9 =3

18/6 =3

9/3 =3

This is a direct variation with a constant of 3

d 5/-7 = -5/7

1/-3 = -1/3

This is not the same so this is not a direct variation

4 0

3 years ago

Read 2 more answers

Consider the equation below. log4 (x+3)=log2 (2+x). Which system of equations can represent the equation?

Verdich [7]

Using: loga b = log b / log a
1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4
2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2

Answer:
y1=log (x+3) / log 4, y2= log (2+x) / log 2

4 0

2 years ago

Read 2 more answers

.

kipiarov [429]

Time from October 5 to January 16
T=26+30+31+16=103 days
I=1870*0.11*103/365=58.05

5 0

3 years ago

You have 4 one-dollar bills and 4 five-dollar bills in your piggy bank. You select two bills at random, with replacement. What i

Mkey [24]

The probability that one would have selected 2 five-dollar bills is; 1/4.

<h3>What is the probability you will have selected 2 five-dollar bills?</h3>

It follows from the task content that the piggy bank contains; 4 one-dollar bills and 4 five-dollar bills to make a total of 8 bills.

Hence, provided the probability events are carried out with replacement, the probability to have selected 2 five-dollar bills is;

= 4/8 × 4/8

= 1/4.

7/8=?/48 A.42 B.13 C.1 D.6