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3 years ago

I NEED HELP! If you help you get 10 points!

Mathematics

1 answer:

gogolik [260]3 years ago

8 0

I would say it's 2.25

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6. Matthew is planning to build a right triangular

saul85 [17]

The answer to this question will be B

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3 years ago

A recipe calls for 4 carrots for every 2 cups of water. Which expression can be used to find the number of carrots needed

Arada [10]

Answer:

4 divided by 2 = 2 so 2carrots per cup of water

Step-by-step explanation:

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3 years ago

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The value of y varies directly with the value of x. When y = 24, x = 4. What is the value of x when y = 48?

Bogdan [553]

Answer:

24/6=4

48/6= 8

so x=8

Step-by-step explanation:

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3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

If no (A) = 40%, no (B) = 30%, n (A∩B) = 20% then find n (<br> (A B)<br> using formula.

Vesnalui [34]

Answer:

solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).

Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,

n(A∪B)=n(A)+n(B)−n(A∩B)

⇒40=20+30−n(A∩B)

⇒40=50−n(A∩B)

⇒n(A∩B)=50−40

⇒n(A∩B)=10

Hence, n(A∩B)=10

Step-by-step explanation:

hope it helps you friend ☺️

8 0

2 years ago

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