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kiruha [24]
3 years ago
9

Pls hurry on the bottom i9s what web its on pls pls hurry

Mathematics
2 answers:
sashaice [31]3 years ago
8 0
The answer to ur question will be A
Vaselesa [24]3 years ago
3 0
The answer is A, as it is 3 over on the x axis and 12 up on the y
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1. Explain the difference between rate and unit rate using their definitions.
Lostsunrise [7]
A rate is a non simplified ratio so a rate could be

4:2=rate
the UNIT rate=the simplest for or 2:1

so exg
300 jumps in 3 days=rate
100 jumps per day=unit rate
3 0
2 years ago
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If y=2x-3 find the value of y when x=2
Evgesh-ka [11]
Y = 2x - 3
Y = 2(2) - 3
Y = 4 - 3
Y = 1.

The y value or y coordinate is 1.
8 0
3 years ago
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Can I get some help I’ll mark brainliest
iren2701 [21]
Itzzzzz 13/15 in simplest form
4 0
2 years ago
I just need help with first 2! Show work please it’s due soon and round answers to the nearest tenth !!!
natima [27]

Answer:

1. To find the volume of a cylinder you'll need to use the formula V = pi(r)^2(h)

V = pi(4)^2(6)

V = 301.59

Rounded* = 301.6

2. A beach ball is a sphere, so we're going to use the formula 4/3pi(r)^3

4/3pi(18)^3

D =  24429.02

Rounded* = 24429.0

I cant read the last one completely, hope this helps.

5 0
2 years ago
A real estate agent wants to know how many owners of homes worth over​ $1,000,000 might be considering putting their home on the
JulsSmile [24]

Answer:

NO

Step-by-step explanation:

The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:

  1. N: The number of observations in the population.
  2. n: The number of observations in the sample.
  3. The way that the random sample is chosen.

We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is

μ_x=p

σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]

In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:

σ_x = σ / sqrt(n).

6 0
2 years ago
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