Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
1 ounce = 28.3495 grams
13 x 28.3495 = 368.544 grams
round answer as needed
Answer:
The answers are as follows for the functions.
f(1) = 12
f(3) = 22
f(5) = 32
Step-by-step explanation:
To find any of these, simply input the value in for x in the equation given.
f(1)
f(x) = 5x + 7
f(x) = 5(1) + 7
f(x) = 5 + 7
f(x) = 12
You can repeat this for each of them and it will allow you to use all of the numbers in the equations given.
TeX rendering has been iffy at best on this site for the past few days, at least in my experience. I've attached a solution below.
Let us suppose the width is x feet
the length is given 12 feet
Perimeter of teh garden = 2( Length + width )= 2( 12+ x)
Fencing required = perimeter of garden
36 = 2( 12+x)
36 = 2*12 + 2x
36 = 24 + 2x
36-24 = 2x
12 = 2x
12/2 = x
6 = x
Width = x feet = 6 feet .Answer .