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djverab [1.8K]
3 years ago
10

Lucy deposits $200 into an account that pays simple interest at a rate of 2% per year. How much interest will she be paid in the

first 4 years? Lucy deposits $200 into an account that pays simple interest at a rate of 2% per year. How much interest will she be paid in the first 4 years?
Mathematics
1 answer:
kumpel [21]3 years ago
8 0
Split this up into the four years.

For the first year, multiply 200 x .02 to get 4
Add 4 onto your total. ($204.00)

For the second year multiply 204 x .02 to get 4.08
Add 4.08 onto your total. ($208.08)

For the third year multiply 208.08 x .02 to get 4.1616 but round to 4.16
Add 4.16 onto your total ($212.24)

For the fourth year multiply 212.24 x .02 to get 4.2448 but round to 4.24
Add 4.24 onto your total (216.48)

Now subtract 200 from your total

216.48-200 = 16.48

She will be payed $16.48 in interest.
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A picture frame (see figure) has a total perimeter of 3 feet. The width of the frame is 0.64 times its length. Find the dimensio
Naya [18.7K]

Answer:

\approx 0.59\text{ ft by }0.91\text{ ft}

Step-by-step explanation:

Let \ell represent the length of the rectangle. The width can be represented as 0.64\ell.

The perimeter of a rectangle with lengths l and w is given by p=2l+2w.

Thus, we have:

2\ell+2(0.64\ell)=3,\\2\ell +1.28\ell=3,\\3.28\ell=3,\\\ell=0.91463414634\approx 0.91

The width is then 0.64(0.91463414634)=0.58536585365\approx 0.59.

8 0
3 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

7 0
3 years ago
Create your own real-world example of a relation that is a function. Domain: The set of Range: The set of
ivanzaharov [21]

Answer:

C(t)=5000 -10t

Step-by-step explanation:

There are many examples in the real world of relationships that are functions.

For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.

If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

C(t)=C_{0}-at\\

Where:

C (t): Amount of water in the tank as a function of time

C_{0}: Initial amount of water in the tank at time t = 0

a: amount of water lost per hour

t: time in hours

Then the equation is:

C(t)=5000 -10t

The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.

Its domain is the set of all positive real numbers t between [0,500]

Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty

Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres

7 0
3 years ago
Read 2 more answers
If the nth term of an AP is (7-4n) then its common difference is​
Hitman42 [59]

Given nth term of an AP = 7-4n

Put n = 1 then t1 = 7-4(1) = 7-4 = 3

Put n = 2 then t2 =7-4(2) = 7-8 = -1

Common difference = t2-t1 = -1-3 = -4

3 0
3 years ago
Help me ASAP please!!!
tia_tia [17]

swimming pool is full

6 0
3 years ago
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