Answer:
y-7= -1/5x
Step-by-step explanation:
general formula (y-y1)= m(x-x1)
m is the slope and in this case m=-1/5
(x1, y1) is a point on thhe line in this case is (0, 7) because f(x)=y
substitute your given in the equation
(y-7) = -1/5(x-0)
y-7= -1/5x
It would be 11,000 to the nearest thousand.
the sugar is sold at rupees 5.4 per kg at a loss of 10% at what price should it be sold per kg to earn a profit of 20%
Answer:
7.2 rupees
Step-by-step explanation:
Given that at a loss of 10 percent which is 90% price, we have sugar sold at 5.4 rupees per k.g
Hence, at 100 percent we have => 5.4 × (100 ÷ 90 )= 6 rupees per kg.
Therefore, at 100 percent, where we have 6 rupees per kg, to make a profit of 20% we have
6 rupees per kg x 120% = 6 × 1.2 = 7.2 rupees per kg.
Hence, the final answer is 7.2 rupees per kg to make a profit of 20%.
When you're given a parallel line, that means you know that both lines should have the same slope m.
And you're given a point (x,y) so you plug in the x for
in the equation and y for
in the equation.
Also plug in m because that was given.
y -
= m(x -
)
Then you can simplify the equation to get y = mx + b
