Answer:
y=6x-38
Step-by-step explanation:
That's the answer for C
Answer:
<h2>3500</h2>
Step-by-step explanation:
Given the ratio of the profit, cost of materials and labour in the production of
an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25
If the cost of labour is x, the cost of material will be 840+x (since the cost of materials is Le 840 more than that of labour) .
Let the total cost of producing the article be y.
Cost of labour = 13/25 * y = x
Cost of labour = 13y/25 = x.................... 1
Cost of material = 7/25*y = 840+x
Cost of material = 7y/25 = 840+x ..................... 2
From 1, 13y = 25x
x = 13y/25 ................... 3
Substituting equation 3 into 2:
7y/25 = 840+x
7y/25 = 840+13y/25
collect the like terms:
7y/25 - 13y/25 = 840
-6y/25 = 840
-6y = 25*840
y = 25*840/6
y = 3,500
<em>Hence the total cost of producing the article is 3500</em>
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
__
The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
It would be 60.
a(b)^x
Since a/ 60 would represent initial value.
Answer:
Step-by-step explanation:
volume =1/3×base area×height
216=1/3× A×6
base area=216/2=108 in²
