The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
I would say 465 since they go back and forth twice which is 155 x 3
A=p(1+i/m)^mn
A=980×(1+0.08÷4)^(4×5)
A=1,456.23
Answer:
One solution: x=2.4, y=0.2
Step-by-step explanation:
x-2y=2
y=-2x+5
x-2(-2x+5)=2
x+4x-10=2
5x=2+10=12
x=12:5=2.4
y=-2x+5=-2*2.4+5=-4.8+5=0.2