If x = -1/2 is a solution of the quadratic equation 3x2+2kx-3=0 find the value of k
2 answers:
6+2k(-1/2)-3=0.
6+1k-3=0
3+1k=0
-3
k=-3
Just substitute for x :)
3(-1/2)2+2k(-1/2)-3=0
-3 + (-1k) -3 = 0
-6 + (-1k) = 0
+6 +6
-1k = 6
/-1 /-1 <u>k = -6 </u> that's what i believe the answer is
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