I believe the answer is b.
Answer:
There are two possibilities:
and 
and 
Step-by-step explanation:
Mathematically speaking, the statement is equivalent to this 2-variable non-linear system:


First,
is cleared in the first equation:

Now, the variable is substituted in the second one:

And some algebra is done in order to simplify the expression:


Roots are found by means of the General Equation for Second-Order Polynomials:
and 
There are two different values for
:






There are two possibilities:
and 
and 
Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c =
= 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !