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3 years ago

What is the answers to these questions

Mathematics

1 answer:

Vsevolod [243]3 years ago

3 0

Answer:

1. equation

2.equation

3.equation

4. expression

5.expression

6.equation

7.expression

8.equation

9.expression

anything with = is an equation, without is expression.

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Express 34 as a pencentage

Colt1911 [192]

34 as a percent is 3400%

In order to get this number you move the decimal to places to the right:
34.0 ---> 3400.0 =
3400%

7 0

3 years ago

Read 2 more answers

Rewrite 302+40=342 in a different way, using the commutative of addition

bagirrra123 [75]

Answer:

40+32=342

Step-by-step explanation:

Using the commutative of addition change the position of 302 and 40 the expression is 40+302=342 [analysis]

7 0

1 year ago

Add.

Sidana [21]

Answer:

1 $\frac{7}{20}$

Step-by-step explanation:

1. Convert the mixed number to an improper fraction to match the rest of the problem (this just makes it easier for now, the answer will still be a mixed number)

-1 $\frac{4}{5}$ becomes $\frac{9}{5}$

2. Re-write the new equation. When there is a "+" in front of a set of parentheses the expression doesn't change aside from removing the plus signs.

The new equation becomes

$\frac{9}{5} - \frac{1}{4} -\frac{1}{5}$

3. Calculate. Just work out the new expression.

The answer is $\frac{27}{20}$

4. Convert to a simplified mixed decimal.

27 goes into 20 once with seven left over, making the answer 1 $\frac{7}{20}$

8 0

2 years ago

F(x) = -x^3+ 6x – 7 at x = 2

vodomira [7]

Answer:

f(2)= -4

Step-by-step explanation:

f(x)= -x^3 + 6x - 7

f(2) = -2^3 + 6*2 - 7

f(2)= -8 +12 -7

f(2)= 3-7

f(2)= -4

4 0

3 years ago

Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a

Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .