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Ivahew [28]
3 years ago
8

Finding Account Balances In Exercise, complete the table to determine the balance A for P dollars Invested at rate for years com

pounded time per year.
n 1 2 4 12 365 Continuous compounding
A
P = $7000, r = 6%, t = 20 years
Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:

i have no idea

Step-by-step explanation:

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5(x+9) distribute five time x plus nine...........???
Tema [17]
Using distributive property, it would become 14x.
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4 years ago
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I got 7 to go :( help plz
gladu [14]

Answer:

I think the second one is the answer ; 2√b

8 0
3 years ago
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If Jake buys 3 new shirts, how many of them would you expect to be t-shirts, and how many would you expect to be collared?
Sophie [7]

Answer:

2 t-shirts ; 1 collar shirt

Step-by-step explanation:

We need to first obtain the ratio of T - shirts to collar shirts :

T - shirts = 10

Collar shirts = 5

Ratio = T - shirts / Collar shirts = 10 / 5 = 2 /1 = 2:1

Hence, using the ratio obtained ; if Jake buys 3 new shirts :

Number of T-shirts :

(Ratio of t-shirts / total ratio) * new t-shirts

2/3 * 3 = 2 t-shirts

Collar shirts :

1/3 * 3 = 1

2 t-shirts ; 1 collar shirt

4 0
3 years ago
I need answer Immediately pls!!!!!!
Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

3 0
3 years ago
I need help with this
Sloan [31]
That equals 27 hope this helps
3 0
3 years ago
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