All categories

3 years ago

Jim drank 2/3 of his water bottle and John drank 3/10 of his water bottle how much water did both the boys drink ?

Mathematics

1 answer:

Likurg_2 [28]3 years ago

4 0

Answer:

29/30

Step-by-step explanation:

first, we must make sure they have the same denominator!

2/3 x 10/10 = 20/30

3/10 x 3/3 = 9/30

20/30 + 9/30 = 29/30

You might be interested in

PLEASEEE HELLPPP!!!!!!!!

belka [17]

Answer:

4.25 i think

Step-by-step explanation:

sorry i have not done these in a while it might be wrong

5 0

3 years ago

What was Mike's average rate of descent over his last three hours?

Romashka [77]

Answer:

The average rate of descent over the last 3 hours is 1000 ft/h.

Step-by-step explanation:

Rate of Change

It's usually referred to as to the variation that one magnitude has in reference to another. The reference magnitude can be time t. The rate of change is calculated as the slope of the curve that represents the function.

The image shows the variation of Mike's height above sea level in feet with time in hours. We need to calculate the rate of change in the last three hours (from 7 to 10).

The rate of change can be calculated with the slope of the line, which formula is:

$\displaystyle m=\frac{h_2-h_1}{t_2-t_1}$

Let's pick two points (7,4000) (10,1000):

$\displaystyle m=\frac{1000-4000}{10-7}=\frac{-3000}{3}=-1000$

$m=-1000\ ft/h$

Note the rate of change is negative, which means the height is decreasing.

The average rate of descent over the last 3 hours is 1000 ft/h.

8 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0

2 years ago

3sina-4sin4a/sin5a if a=-45 degree

Ierofanga [76]

Given:

The given expression is:

$\dfrac{3\sin a-4\sin 4a}{\sin 5a}$

To find:

The value of the given expression at $a=-45$ .

Solution:

We have,

$\dfrac{3\sin a-4\sin 4a}{\sin 5a}$

Substituting $a=-45$ , we get

$\dfrac{3\sin (-45)-4\sin [4(-45)]}{\sin [5(-45)]}$

$=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (225)}$

$=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (180+45)}$

$=\dfrac{-3\sin (45)+4\sin (180)}{\sin (45)}$

On substituting $\sin (180)$ , we get,

$=\dfrac{-3\sin (45)+4(0)}{\sin (45)}$

$=\dfrac{-3\sin (45)+0}{\sin (45)}$

$=\dfrac{-3\sin (45)}{\sin (45)}$

$=-3$

Therefore, the value of the given expression at $a=-45$ is $-3$ .

8 0

3 years ago

Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, squ

vivado [14]

Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.

5 0

4 years ago

Read 2 more answers