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2 years ago

If sin A = 3/4, then the value of tan A

Mathematics

1 answer:

Schach [20]2 years ago

8 0

$sinA=\frac{3}{4}$ ⇒ ∠A ≈ 49°

tanA ≈ 1.15

ok done. Thank to me :>

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Helpppp meeee plzzzzz

krek1111 [17]

Answer:

Step-by-step explanation:

As the hypotenuse is not equal to base and perpendicular.

7 0

3 years ago

A recipe for 12 apple cinnamon muffins calls for 1 cup of flour. The number of muffins that can be made varies directly with the

White raven [17]

Answer:

21 muffins

Step-by-step explanation:

1 cup will get you 12 muffins. Since you have 3/4 cups left over, you have to find 3/4 of 12. 1/4 is equal to 3. 3x3 equals 9. 12+9 equals 21.

6 0

3 years ago

Triangle ABC is similar to triangle PQR , As shown below :

Rina8888 [55]

Answer:

Option C is correct

Step-by-step explanation:

In similar triangles corresponding sides are in same ratio.

Notice that sides b and q are corresponding ( they are opposite equal angles) and so are a and p

5 0

3 years ago

When 3(2x + 5) is added to 2(2x − 4) the resulting expression is?

velikii [3]

Answer:

10x + 7

Step-by-step explanation:

3(2x + 5) added to 2(2x - 4) is the same as 3(2x +5) + 2(2x - 4)

Remember PEMDAS

P – Parentheses (distribution)

E – Exponents

M – Multiplication

/D – Division (whichever comes first from left to right)

A – Addition

/S – Subtraction (whichever comes first from left to right)

First, we will distribute the left side.

3(2x + 5)

3 * 2x = 6x

3 * 5 = 15

Add them together to get:

6x + 15

6x + 15 + 2(2x - 4)

We must now distribute the right side.

2 * 2x = 4x

2 * -4 = -8

Add them together to get:

4x -8

We now have:

6x + 15 + 4x - 8

<u>Let's combine like terms.</u>

6x and 4x are like terms.

Combine: 6x + 4x = 10x

15 and -8 are like terms.

15 - 8 = 7

Now we have 10x + 7

Since 10 and 7 don't have any GCF, we have our answer.

10x + 7

~ $InLoveWithPugs$

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8 0

2 years ago

The vertex of a parabola represented by f(x)=x^2 - 4x + 3 has coordinates (2,-1). Find the coordinates of the vertex of the para

Step2247 [10]

$f(x)=x^2-4x+3$
a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:
$f(x)=a(x-p)^2+q$
$f(x)=1(x-2)^2-1$

We need to put (x-2) at the place of (x) in f(x) equation to get g(x)
$g(x)=1[(x-2)-2]^2-1$
$g(x)=(x-2-2)^2-1$
$g(x)=(x-4)^2-1$
So:
p=4, q=-1

Vertex of the parabola defined by g(x)=f(x-2) has the vertex at $\boxed{(4;-1)}$

:)

7 0

2 years ago