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Kruka [31]
3 years ago
5

When h has the value of 4 calculate 5h-3

Mathematics
2 answers:
Margaret [11]3 years ago
6 0
5h - 3 = 17

First, substitute h for 4 and the equation becomes 5(4)-3
Then, use PEMDAS (order of operations) to answer.
5 x 4 = 20
20 - 3 = 17
hram777 [196]3 years ago
5 0
5(4) - 3, 5 x 4 is 20 and 20 - 3 = 17
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Solve for x in the diagram below.
Sonbull [250]
The answer is x=45…..
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1 year ago
Unit rate for 3 ounces for every 3/4 cup
Vanyuwa [196]

Answer:

4 ounces per cup

Step-by-step explanation:

To find the unit rate, we take the ounces and divide by cups.  We want a 1 in the denominator

3 ounces÷3/4 cup

Copy dot flip

3 ounces * 4/3  per  cup

4 ounces per cup

7 0
3 years ago
If three prime numbers are randomly selected from the prime numbers less than 30 and no prime number can be chosen more than onc
Dmitry [639]

Answer:

C)30%

Step-by-step explanation:

Prime numbers less than 30 are given below

2,3,5,7,11,13,17,19,23,29

We have to find the probability that sum of three prime numbers selected will be even.

We know that

Sum of any three prime number except 2 will be odd.

Total prime numbers except 2=9

Total prime numbers=10

Probability:P(E)=\frac{favorable\;cases}{total\;number\;of\;cases}

Probability of getting sum of three prime numbers selected will be odd=\frac{9C_3}{10C_3}

nC_r=\frac{n!}{r!(n-r)!}

By using formula

Probability of getting sum of three prime numbers selected will be odd=P(E)=\frac{\frac{9!}{3!6!}}{\frac{10!}{3!7!}}=\frac{9!}{3!6!}\times \frac{3!\times 7\times 6!}{10\times 9!}

Probability of getting sum of three prime numbers selected will be odd=P(E)=0.7

Probability of getting sum of three prime numbers selected will be even=P(E')=1-0.7=0.3=0.3\times 100=30%

By using formula P(E')=1-P(E)

3 0
2 years ago
Samantha reports that 60% of the first year students at her university think they should be able to bring a car to campus. She a
Nostrana [21]

Answer:

D) the standard error for her sample is 15

Step-by-step explanation:

Samantha is 95% certain that between 50% and 70% of the first year students agree that they should be able to bring a car to campus.

Here

  • 95% is the confidence level.
  • The range between 50% and 70% indicates 95% confidence interval.
  • 60% is the average proportion of the first year students at her university think they should be able to bring a car to campus.
  • 10% (0.1) is the margin of error from the mean

Since standard error can be obtained by dividing margin of error by the z-statistic of the confidence level which is 1.96. The standard error for her sample \frac{0.1}{1.96} does not equal to 15.

4 0
3 years ago
Answer correct and fast
inna [77]

Hello there I hope you are having an great Day :)

1) 32780ml = 32.78

2) 37 1/2% of 24 = 9

Hopefully that helps you :)

3 0
2 years ago
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