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aliya0001 [1]
3 years ago
9

Which linear equation is represented by the table?

Mathematics
1 answer:
pentagon [3]3 years ago
6 0

Answer:

On E. the first answer is = -2.5x-15 and the solution is (-6,0)

Step-by-step explanation:

I just guessed this on E. and got it right.

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Find measure angle 3
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Answer:

∠ 3 = 50°

Step-by-step explanation:

∠ 3 and 50° are corresponding angles and congruent, thus

∠ 3 = 50°

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Using the drawing, what's the vertex of angle 4
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Using the four points around the drawing, we can see that angle four is connected to the vertex A. 

The answer I believe is:
D. Vertex A.

Hope I could help! Have a good one.
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What is -2.4 + 6.7 - 3.2 <br><br> Answers: -11.3, 1.1, 2.3, 7
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Answer:

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Merchandise is ordered on November 10; the merchandise is shipped by the seller and the invoice is prepared, dated, and mailed b
natali 33 [55]

Answer:

November 13

Step-by-step explanation:

Following dates are given

On November 10 = Merchandise ordered

Date of an invoice prepared, dated and mailed = November 13

Date when the merchandised received by the buyer = November 18

So, the credit period begins when the invoice is prepared, dated and the mailed by the seller to the buyer as it is the evidence of that the merchandise is ordered            

4 0
3 years ago
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0
3 years ago
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