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Phantasy [73]
3 years ago
6

Why must chemical equations be balanced?

Chemistry
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

to validate the law of conservation of mass as total no. of reactants must be equal to the total no. of products

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It 32g of potassium nitrate can be dissolved in 1cm3 of water at 20oC before a saturated solution is obtained, how much potassiu
Dmitry_Shevchenko [17]

Answer:

160 gm

Explanation:

Five times as much water means you can dissolve 5 times as much potassium nitrate    5 x 32 = 160 gm  <u> <===== this seems unlikely though as I doubt 32 g  of  potassium nitrate will dissolve in only  1 cm^3 of water 1 cm^3 of water is only 1 gm of water </u>

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1 year ago
If you are mixing a solution in a spray bottle with 15 oz of water how much chlorine do you need to add for the correct ratio
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You should add 1 or 2 ounces
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2 years ago
If the stocks in a system always decrease and never increase, the system has what type of feedback loop? (Select the best answer
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A psitive feedback
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3 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
2 years ago
PLEASE HELP MEEE!!!!
Assoli18 [71]
It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
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2 years ago
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