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nika2105 [10]
3 years ago
8

What is basicity in acids?​

Chemistry
1 answer:
timama [110]3 years ago
6 0
Basicity of an acid is the number of hydrogen ions which can be produced by one molecule of an acid
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He diagram shows a device that uses radio waves.
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Your answer is B. Capture, amplify and demodulate waves.

Explanation:

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A desert area has many species of cactus and brush as well as birds, snakes, lizards, and rodents. This desert is an example of
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Answer: Climax Commuity.

Explanation: (hope it’s right! Good luck!)

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When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per
andrezito [222]

The given statement is True.


This is single replacement reaction.

As reactivity decreases down the group,

Iodine is less reactive than Chlorine.  

And so Iodine cannot replace chlorine from FeCl2.

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Which of the following solutions would have [Fe3+] = 0.020 M?
Shalnov [3]

Answer:

None of the given options

Explanation:

Let's go case by case:

A. No matter the volume, the concentration of Fe(NO₃)₃ (and thus of [Fe³⁺] as well) is 0.050 M.

B. We can calculate the moles of Fe₂(SO₄)₃:

  • 0.020 M * 0.80 L = 0.016 mol Fe₂(SO₄)₃

Given that there are two Fe⁺³ moles per Fe₂(SO₄)₃ mol, in the solution we have 0.032 moles of Fe⁺³. With that information in mind we <u>can calculate [Fe⁺³]</u>:

  • 0.032 mol Fe⁺³ / 0.80 L = 0.040 M

C. Analog to case A., the molar concentration of Fe⁺³ is 0.040 M.

D. Similar to cases A and C., [Fe⁺³] = 0.010 M.

Thus none of the given options would have [Fe⁺³] = 0.020 M.

7 0
2 years ago
A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0
larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = ?

n = number of moles of gas  = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 25^oC=273+25=298K

V_1 = initial volume of gas  = 25 mL

V_2 = final volume of gas  = 75 mL

Now put all the given values in the above formula, we get:

w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})

w=2.722J

Therefore, the work done by the system is, 2.2722 J

8 0
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