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erik [133]
2 years ago
11

(1) Complete the word equation for the complete combustion of methane in

Chemistry
1 answer:
Deffense [45]2 years ago
6 0

Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.

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The difference between diffusion and osmosis is that osmosis deals only with ________.
Nat2105 [25]
Osmosis deals only with D. Water. Diffusion and Osmosis are relatively the same thing besides the fact that water is largely incorporated with the osmosis.
6 0
3 years ago
Consider this reaction mechanism: Step 1: Mo(CO)6→ Mo(CO)5 + CO Step 2: Mo(CO)5 + P(CH3)3→ Mo(CO)5P(CH3)3 Which of these is an i
Alja [10]

Answer:

Mo(CO)5 is the intermediate in this reaction mechanism.

Explanation:

The reaction mechanism describes the sequence of elementary reactions that must occur to go from reactants to products. Reaction intermediates are formed in one step and then consumed in a later step of the reaction mechanism.

In this reaction mechanism, Mo(CO)5 is the product of 1st reaction and then it is used as a reactant in 2nd reaction. So, Mo(CO)5 is the reaction intermediates.

The overall balanced equation would be,

Mo(CO)6 + P(CH3) ↔ CO + Mo(CO)5 +  P(CH3)3

4 0
2 years ago
How many moles of carbon dioxide will be produced from the complete combustion of 13.6 moles of butane?
Aleks04 [339]

Answer:

54.4 mol

Explanation:

the equation for complete combustion of butane is

2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O

molar ratio of butane to CO₂ is 2:8

this means that for every 2 mol of butane that reacts with excess oxygen, 8 mol of CO₂ is produced

when 2 mol of C₄H₁₀ reacts - 8 mol of CO₂ is produced

therefore when 13.6 mol of C₄H₁₀ reacts - 8/2 x 13.6 mol = 54.4 mol of CO₂ is produced

therefore 54.4 mol of CO₂ is produced

5 0
3 years ago
Which compound has the highest percent composition by mass of strontium
8090 [49]
So if the compound has the smallest gram formula mass it has the highest percentage composition by mass of strontium
3 0
3 years ago
What is the ph of a soft drink in which the major buffer ingredients are 6.6 g of nah2po4 and 8.0 g of na2hpo4 per 355 ml of sol
Alex777 [14]
The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
                                                   = 0.055 moles of NaH2PO4 which is also equal to the number of moles of H2PO4.
[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
  = 0.055/ ( 355 ×10^-3)
  = 0.155 M
Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)

1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
                                             = 0.0563 moles
 [HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
     = 0.0563/(355×10^-3)
     =  0.1586 M
Both H2PO4^2- and HPO4^2- are weak acids the undergoes partial dissociation 
Ka of H2PO4- = 6.20 × 10^-8
 [H+] =Ka*([H2PO4-]/[HPO4(2-)]
        = (6.20 ×10^-8)×(0.155/0.1586)
        = 6.059 ×10^-8 M
pH = - log[H+]
     = - log (6.059×10^-8)
     = 7.218

5 0
3 years ago
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