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erik [133]
2 years ago
11

(1) Complete the word equation for the complete combustion of methane in

Chemistry
1 answer:
Deffense [45]2 years ago
6 0

Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.

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A 111.6 gram sample of iron (MW=55.8) was heated from 0 degrees C to 20 degrees C. It absorbed 1004 Joules of energy. What is th
qwelly [4]
Use the equation q=ncΔT.
q= heat absorbed our released (in this case 1004J)
n= number of moles of sample ( in this case 2.08 mol)
c=molar heat capacity 
ΔT=change in temperature (in this case 20°C)
You have to rewrite the equation for c.
c=q/nΔT
c=1004J/(2.08mol x 20°C)
c=24.1 J/mol°C
 
I hope this helps
7 0
2 years ago
Drops of a clear liquid are added to a red liquid. As the drops are added, the red liquid becomes orange, then yellow
lakkis [162]
This must be a universal indicator, the pH is going down everytime you add more :)
3 0
3 years ago
Read 2 more answers
Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr
lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Using the equation,

ΔT_{f} = iK_{f}m

where:

ΔT_{f} = change in freezing point (unknown)

i = Van't Hoff factor

K_{f} = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = \frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }

molal concentration = 0.1219m

Now, putting in the values to the equtaion ΔT_{f} = iK_{f}m we get,

ΔT_{f} = 2 × 1.86 × 0.1219

ΔT_{f} = 0.4536°C

So, ΔT_{f} of solution is,

ΔT_{f_{solution} } = 0.00°C - 0.45°C

ΔT_{f_{solution} } =  - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Learn more about freezing point here;

brainly.com/question/3121416

#SPJ4

7 0
1 year ago
What is ultrafication?
Studentka2010 [4]
<span>Ultrafiltration is a process which prevents the dilution of the bloos. During this process some of water with some dissolved materials is forced </span>through the membrane by maintaining the blood at a higher pressure than the solution.
6 0
3 years ago
A car traveling at a constant speed travels 175 miles in four hours. How many minutes will it take for the car to travel 1000 fe
elena-14-01-66 [18.8K]

It takes 0.26 minutes to travel 1000 feet

<u>Solution:</u>

Given that car traveling at a constant speed travels 175 miles in four hours

Distance = 175 miles

Time taken = 4 hours

Convert the units to feet and minute

Given that,

1 mile = 5280 feet

175 miles = 5280 x 175 feet = 918720 feet

Also we know that,

1 hour = 60 minutes

4 hours = 60 x 4 minutes = 240 minutes

Thus, we got,

Distance = 918720 feet

Time taken = 240 minutes

<em><u>Find the speed of car</u></em>

<em><u>Speed is given by formula:</u></em>

speed = \frac{distance}{time}

speed = \frac{918720}{240} = 3828

Thus speed of car is 3828 feet per minute

<em><u>How many minutes will it take for the car to travel 1000 feet?</u></em>

Let "x" be the minutes needed for 1000 feet

speed of car is 3828 feet per minute

1 minute = 3828 feet

x minute = 1000 feet

This forms a proportion. We can solve by cross multiplying

x \times 3828 = 1000 \times 1\\\\x = \frac{1000}{3828}\\\\x = 0.26

Thus it takes 0.26 minutes to travel 1000 feet

7 0
3 years ago
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