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3 years ago

Cu + 2AgNO3 es002-1.jpg 2Ag + Cu(NO3)2 How many moles of copper must react to form 0.854 mol Ag?

1 answer:

4 0

Balance Chemical Equation is as follow,

<span> Cu + 2 AgNO</span>₃ → 2 Ag + Cu(NO₃)₂

According to Balance Equation,

2 Moles of Ag is produced by reacting = 1 Mole of Cu
So,
0.854 Moles of Ag will be produced by reacting = X Moles of Cu

Solving for X,
X = (0.854 mol × 1 mol) ÷ 2 mol

X = 0.427 Moles of Cu
Result:
0.854 Moles of Ag are produced by reacting 0.427 Moles of Cu.

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Convert 4.92 L of hydrogen at STP to moles.

Lorico [155]

${\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}$

$\sf C) \: 0.220 \: mol \: H_2$

Explanation:

1 mol = 22.4 litres

4.92 = how many moles?

$\sf \implies \frac{4.92}{22.4} \\ \\ \sf \implies 0.2196 \\ \\ \sf \implies 0.220 \: mol \: H_2$

5 0

2 years ago

Read 2 more answers

The normal boiling point for acetone is 56.5°c. at an elevation of 5300 ft the atmospheric pressure is 630. torr. what would be

Flauer [41]

20.5 because the boiling point should decrease not increase

7 0

3 years ago

A forensic chemist is given a white powder for analysis. She dissolves 0.50 g of the substance in 8.0 g of benzene. The solution

Sholpan [36]

Answer:

The given compound cannot be cocaine.

Explanation:

The chemist can comment on the nature of compound being cocaine or not from the depression in freezing point.

Depression in freezing point of is related to molality as:

Depression in freezing point = Kf X molality

Where

Kf = cryoscopic constant = 4.90°C/m

depression in freezing point = normal freezing point - freezing point of solution

depression in freezing point = 5.5-3.9 = 1.6°C

1.6°C = 4.90 X molality

$molality=\frac{1.6}{4.90} = 0.327 m$

we know that:

$molality=\frac{moles}{mass of solvent(kg)}=\frac{moles}{0.008kg}$

therefore

moles = 0.327X0.008 = 0.00261 mol

$moles=\frac{mass}{molarmass}$

$molarmass=\frac{mass}{moles}=\frac{0.50}{0.00261}= 191.57g/mol$

The molar mass of cocaine is 303.353

So the given compound cannot be cocaine.

3 0

3 years ago

How might the molecules inside an ice pack be different from the liquid inside of an insulated cup?

MatroZZZ [7]

Answer:

The molecules inside the ice pack are frozen therefore they are stuck in place. The molecules inside an insulated cup aren't frozen but still stuck inside of their container so that they can not fly out.

Explanation:

5 0

3 years ago

H3PO4 + Ca(OH)2 → Ca(H2PO4)2 + H2O

aniked [119]

Given question is incomplete. The complete question is as follows.

Balance the following equation:

$H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O$

Answer: The balanced chemical equation is as follows.

$2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O$

Explanation:

When a chemical equation contains same number of atoms on both reactant and product side then this equation is known as balanced equation.

For example, $H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O$

Number of atoms on reactant side:

H = 5

P = 1

O = 6

Ca = 1

Number of atoms on product side:

H = 6

P = 2

O = 9

Ca = 1

In order to balance this equation, we will multiply $H_3PO_4$ by 2 on reactant side and we will multiply $H_2O$ by 2 on product side. Hence, the balanced chemical equation is as follows.

$2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O$

8 0

3 years ago